Full_Name: Paul Louisell
Version: 1.6.2
OS: Windows NT
Submission from: (NULL) (192.249.47.9)
There is a slight bug in the function 'any'. Given a logical vector (possibly
including values of 'NA'), the default action of any should be as follows:
(i) at least one value = T should return T
(ii) NO values = T
(a) at least one value = 'NA' should return 'NA'
(b) all values = F should return F
The problem is that the default action of 'any' is using the following rule:
(i) at least one value = 'NA' returns 'NA'
(ii) NO values = 'NA'
(a) at least one value = T returns T
(b) all values = F returns F
This is illustrated in the code below
> test=1:5
> is.na(test)[5]=T
> test
[1] 1 2 3 4 NA
> any(test==3)
[1] NA
> any(test==5)
[1] NA
> any(test[1:4]==5)
[1] FALSE
> any(test[1:4]==3)
[1] TRUE
The bug is easily fixed by the user, but someone may want to correct this if
he/she can find time.
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