The fact that an attempt at adding an unordered and an ordered factor gives an
error
1. is not a bug (at least I can't imagine why it would be so)
2. has nothing to do with latticeParseFormula
Also, I very much doubt that getting a bunch of NA's and a warning (which you
seem to have omitted from your output) is really what you anticipated when
you added two (unordered) factors.
Please first report what you think are bugs on r-devel before filing bug
reports.
On Monday 03 March 2003 06:04 pm, [EMAIL PROTECTED] wrote:
> This feels like inconsistent behavior. latticeParseFormula works the
> way I anticipated for factor, but not for ordered. I want the
> behavior I see with tmp2, but not with tmp. My next step is to use
> the right.name to isolate the tmp2[,c("a","b")] columns.
>
>
> tmp <- data.frame(y=(1:12)+.1,
> a=factor(rep(1:3,4)),
> b=ordered(rep(1:4, c(3,3,3,3))))
> latticeParseFormula(as.formula(y ~ a + b), data=tmp)
>
> tmp2 <- data.frame(y=(1:12)+.1,
> a=factor(rep(1:3,4)),
> b=factor(rep(1:4, c(3,3,3,3))))
> latticeParseFormula(as.formula(y ~ a + b), data=tmp2)
>
> > version
>
> _
> platform i386-pc-mingw32
> arch i386
> os mingw32
> system i386, mingw32
> status
> major 1
> minor 6.2
> year 2003
> month 01
> day 10
> language R
>
> > tmp <- data.frame(y=(1:12)+.1,
>
> + a=factor(rep(1:3,4)),
> + b=ordered(rep(1:4, c(3,3,3,3))))
>
> > latticeParseFormula(as.formula(y ~ a + b), data=tmp)
>
> Error in a + b : non-numeric argument to binary operator
>
> > tmp2 <- data.frame(y=(1:12)+.1,
>
> + a=factor(rep(1:3,4)),
> + b=factor(rep(1:4, c(3,3,3,3))))
>
> > latticeParseFormula(as.formula(y ~ a + b), data=tmp2)
>
> $left
> [1] 1.1 2.1 3.1 4.1 5.1 6.1 7.1 8.1 9.1 10.1 11.1 12.1
>
> $right
> [1] NA NA NA NA NA NA NA NA NA NA NA NA
>
> $condition
> NULL
>
> $left.name
> [1] "y"
>
> $right.name
> [1] "a + b"
>
>
>
> Rich
>
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