On Tue, 12 Aug 2003, Thomas Lumley wrote: > On Wed, 13 Aug 2003 [EMAIL PROTECTED] wrote: > > > If all rows are in the same "group", rowsum() returns a vector instead of a > > (1xN) matrix, contrary to documentation: > > > > Yes, and it appears to be deliberate since rowsum.default() ends with > drop(rval), though I don't remember why it was this way. > > Is there a strong preference for changing the function vs changing the > documentation?
I'd change the function. The Therneau original function of this name returns a 1xN matrix, and it is easier to drop() that to reinstate. -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-devel