[EMAIL PROTECTED] wrote:
I guess you get something negative,because the year you have coded is 2011 rather than 1911!
yes, you are correct!
I'm using a routine for file format transform
output_file <- leSRHchron(input_file)
So you know how to solve it now? If not, what is leSRHchron()???
Uwe Ligges
and other routine for save output_file, but, in the output_file, year is save in short format.
thank you,
Juan.
Em Qui, 2004-11-04 Ãs 10:43, Uwe Ligges escreveu:
[EMAIL PROTECTED] wrote:
Times series of rain and discharge in hydrologic - stations has above 95 years of daily records. In the temporal series over "serie" dataframe, using chron's object:
library(chron) # load chron library
length(serie$data)
[1] 27182
serie$data[length(serie$data)]
[1] (85-12-31 00:00:00) # 1985-dez-31 00:00:00hs
serie$data[1]
[1] (11-08-01 00:00:00) # 1911-aug-01 00:00:00hs
serie$data[length(serie$data)] -serie$data[1] # error, correct value
is: 27181
I guess you get something negative,because the year you have coded is 2011 rather than 1911!
But I cannot be sure because you have not specified any reproducible example. Also, you have not said what the error message is. Which version of R, chron and the OS? Please read the posting guide!
Uwe Ligges
which are the solution?
Juan S. Ramseyer
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