Oops. I had my own as.Date routines loaded. (These
will be made available in the next version of zoo
but here they are in the meantime.)
If you want to get the as.Date(xD:yD) and similar
to come out you should define these:
as.Date.numeric <- function (x, ...)
structure(floor(x + 0.001), class = "Date")
as.Date.integer <- function (x, ...)
structure(x, class = "Date")
Date: Fri, 3 Dec 2004 21:42:37 -0500 (EST)
From: Gabor Grothendieck <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>, <[EMAIL PROTECTED]>
Subject: RE: [Rd] seq.Date requires by
Don't know the answer to your question but note
that chron can do it without by=.
xD <- as.Date("1996-01-01")
yD <- as.Date("1996-12-01")
library(chron)
xc <- chron(xD)
yc <- chron(yD)
seq(xc, yc)
# Also one can do this in either chron or Date:
chron(xc:yc)
as.Date(xD:yD)
Date: Fri, 3 Dec 2004 11:29:08 -0800
From: Vadim Ogranovich <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Subject: [Rd] seq.Date requires by
Hi,
What is the reason for seq.Date to require the 'by' argument and not to
default it to 1 in the example below?
> seq(from=as.Date("1996-01-01"), to=as.Date("1996-12-01"))
Error in seq.Date(from = as.Date("1996-01-01"), to =
as.Date("1996-12-01")) :
exactly two of `to', `by' and `length.out' / `along.with' must be
specified
This is R-1.9.1, but I haven't seen anything pertaining in the release
notes of 2.0.x.
Thanks,
Vadim
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