According to the help page, freq and prob are logical, so this is
correctly an error.
What it actually does is
freq <- if (!missing(probability)) !as.logical(probability)
which is consistent with the documentation.
On Thu, 10 Feb 2005 [EMAIL PROTECTED] wrote:
Full_Name: Tom Hopper
Version: 2.0.1
OS: Windows 2000
Submission from: (NULL) (69.220.229.2)
While attempting to wrap hist() in my own custom function (for formatting
purposes), I notice that a call like
> hist(x, prob=NULL)
produces the output:
Error in if (freq) x$counts else { : argument is of length zero
Switching to use freq does not produce an error, even when freq = NULL.
It appears that hist() is checking for the condition
!missing(prob)
but needs to add a check for a NULL value
&& !is.null(prob)
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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