This is what your example had in it. You can format the data in any format that you want. This is nothing special about ':'.
On 11/2/07, B. Bogart <[EMAIL PROTECTED]> wrote: > Hi Jim, > > Yes that works!!! > > Why the heck do I need to put "%H.%M.%S" when the input format is > "%H:%M:%S" ? ("." in place of ":". > > I see in the help(timeDate) examples where the format is properly > written as "%Y-%m-%d %H:%M:%S" > > So why does this not work: > > > date = timeDate(as.character(inputdate),format="%Y-%m-%d_%H:%M:%S") > Error in if (regexpr("/....", charvec[1])[[1]] > 0) return("%m/%d/%Y") : > missing value where TRUE/FALSE needed > > Thanks so much, I don't see how I could have known I would have to put > "." in place of ":" in the format string. > > B. Bogart > Simon Fraser University > > jim holtman wrote: > > Seems to work fine with this call: > > > > > >> inputdate = "2007-10-31_16.20.22" > >> timeDate(as.character(inputdate),format="%Y-%m-%d_%H.%M.%S") > >> > > GMT > > [1] [2007-10-31 16:20:22] > > > > > > > > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.