On 14/01/2008, Gabor Grothendieck <[EMAIL PROTECTED]> wrote: > Its not related to scoping. f(b = 10) passes 10 as argument b > but f(b <- 10) assigns to variable b (which has nothing to do with > argument b) and then passes the result of the b<-10 expression (which is > 10) to f. Since no argument was specified it uses positional > matching and the first position is argument a. Thus its the same > as f(10). Note that f(b<-10) isthe same as f( (b <- 10) ) which may > make it clearer.
Of course! Straightforward! Many thanks, Mark -- Dr. Mark Wardle Specialist registrar, Neurology Cardiff, UK ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
