Dear all,
It appears that the function is.factor() returns different results when
used inside the apply() function: that is, is.factor() fails to
recognize a factor..
Where is the trick?
many thanks,
vito
> df1<-data.frame(y=1:10,x=rnorm(10),g=factor(c(rep("A",6),rep("B",4))))
> is.factor(df1[,1])
[1] FALSE
> is.factor(df1[,2])
[1] FALSE
> is.factor(df1[,3])
[1] TRUE
> is.factor(df1$g)
[1] TRUE
> apply(df1,2,is.factor)
y x g
FALSE FALSE FALSE
>
> R.version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major 2
minor 6.1
year 2007
month 11
day 26
svn rev 43537
language R
version.string R version 2.6.1 (2007-11-26)
>
--
====================================
Vito M.R. Muggeo
Dip.to Sc Statist e Matem `Vianelli'
Università di Palermo
viale delle Scienze, edificio 13
90128 Palermo - ITALY
tel: 091 6626240
fax: 091 485726/485612
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