On Aug 4, 2010, at 1:42 PM, Dimitri Liakhovitski wrote:
I am sorry, I'd like to split my column ("names") such that all the
beginning of a string ("X..") is gone and only the rest of the text is
left.
I could not tell whether it was the string "X.." or the pattern "X.."
that was your goal for matching and removal.
x<-data.frame(names=c("X..aba","X..abb","X..abc","X..abd"))
x$names<-as.character(x$names)
a) Instead of "names" which is heavily used function name, use
something more specific. Otherwise you get:
> names(x)
"names" # and thereby avoid list comments about canines.
b) Instead of coercing a character vector back to a character vector,
use stringsAsFactors = FALSE.
> x<-data.frame(nam1=c("X..aba","X..abb","X..abc","X..abd"),
stringsAsFactors=FALSE)
#Thus is the pattern version:
> x$nam1 <- gsub("X..",'', x$nam1)
> x
nam1
1 aba
2 abb
3 abc
4 abd
This is the string version:
> x<-data.frame(nam1=c("X......aba","X.y.abb","X..abc","X..abd"),
stringsAsFactors=FALSE)
> x$nam1 <- gsub("X\\.+",'', x$nam1)
> x
nam1
1 aba
2 y.abb
3 abc
4 abd
(x)
str(x)
Can't figure out how to apply strsplit in this situation - without
using a loop. I hope it's possible to do it without a loop - is it?
--
David Winsemius, MD
West Hartford, CT
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