Thanks so much, David!

The following codes works!

result.fun <- lapply(1:2, function(i) cv.fold(i, 3, 0.3))





On Tue, Sep 7, 2010 at 3:35 PM, David Winsemius <[email protected]>wrote:

>
> On Sep 7, 2010, at 5:43 PM, Changbin Du wrote:
>
>  cv.fold<-function(i, size=3, rang=0.3){
>>      cat('Fold ', i, '\n')
>>      out.fold.c <-((i-1)*c.each.part +1):(i*c.each.part)
>>      out.fold.n <-((i-1)*n.each.part +1):(i*n.each.part)
>>
>>     train.cv <- n.cc[-out.fold.c, c(2:2401, 2417)]
>>      train.nv <- n.nn[-out.fold.n, c(2:2401, 2417)]
>>
>>      train.v<-rbind(train.cv, train.nv) #training data for feature
>> selection
>>
>>   # grow tree
>> fit.dimer <- rpart(as.factor(out) ~ ., method="class", data=train.v)
>> at<-grep("<leaf>", fit.dimer$frame[, "var"], value=FALSE,
>> ignore.case=TRUE)
>> varr<-as.character(unique(fit.dimer$frame[-at, "var"]))
>>
>>      train.cc <- n.cc[-out.fold.c,]
>>      valid.cc <- n.cc[out.fold.c,]
>>
>>      train.nn <- n.nn[-out.fold.n,]
>>      valid.nn <- n.nn[out.fold.n,]
>>
>>      train<-rbind(train.cc, train.nn) #training data
>>      valid<-rbind(valid.cc, valid.nn) # validation data
>>
>> #creat data set contains the following variables
>> myvar<-names(gh9_h) %in% c(varr, "out")
>>
>>      train<-train[myvar] # update training set
>>      valid<-valid[myvar]
>>
>> nnet.fit<-nnet(as.factor(out) ~ ., data=train,  size=size, rang=rang,
>> decay=5e-4, maxit=500)  # model fitting
>>
>>      #get the validation error
>>    mc<-table(valid$out, predict(nnet.fit, valid, type="class")) #confusion
>> matrix
>>
>>      fp<-mc[1,2]/sum(mc[1,]) #false positive
>>      fn<- mc[2,1]/sum(mc[2,]) #false negative
>>     accuracy.r<-1-(mc[1,2]+mc[2,1])/sum(mc) #total accuracy rate
>>
>> return(c(fp, fn, accuracy.r))
>>
>>                              }
>>
>> result.fun <- lapply(1:2, cv.fold(i, size=5, rang=0.3))
>>
>> I got the following error message:
>>
>> *Error in match.fun(FUN) :
>>  'cv.fold(i, size = 5, rang = 0.3)' is not a function, character or symbol
>>
>
> Generally when one is passing an atomic vector argument to a function one
> would use sapply (but it may be a distinction withou a difference here.) ...
> and furthermore the additional arguments would be given as named constants:
>
> ?sapply
>
> Perhaps (untested):
>
>  result.fun <- sapply(1:2, cv.fold, size=5, rang=0.3))
>
> or perhaps:
>
> result.fun <- sapply(1:2, function(i) cv.fold(i, size=5, rang=0.3))
>
>
> As always the provision of a working example, perhaps even from one of the
> help pages, would allow testing, and it's always good manners to specify
> which package has non-base functions:
>
> > ?n.cc
> No documentation for 'n.cc' in specified packages and libraries:
> you could try '??n.cc'
> > ?rpart
> No documentation for 'rpart' in specified packages and libraries:
> you could try '??rpart'
> > ?train
> No documentation for 'train' in specified packages and libraries:
> you could try '??train'
>
> (I have suspicions which packages they come from, but one never knows....)
>
> --
> David.
>
>
>
>>
>> I do want to change the size and rang parameters some time.
>>
>> *
>> Can anyone help me this this?  Thanks so much!
>>
>>
>> --
>> Sincerely,
>> Changbin
>>
>
>
> David Winsemius, MD
> West Hartford, CT
>
>


-- 
Sincerely,
Changbin
--

Changbin Du
DOE Joint Genome Institute
Bldg 400 Rm 457
2800 Mitchell Dr
Walnut Creet, CA 94598
Phone: 925-927-2856

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