On Sep 8, 2010, at 4:45 PM, jlemaitre wrote:
I have a data frame with two columns:
url.img patt.url
1 http://$IMAGE_ID$ www.url.com/image.jpg
2 $IMAGE_ID$ http://www.blah.com/image.gif
...
I want to replace "$IMAGE_ID$" with the corresponding entry in the
pattern
column such that the result would appear as follows:
A) Drop the use of the name "pattern" because it is the argument name
for regex functions. Name it something else like "patt.url".
Furthermore "image" is also a function name so use somehting more
specific there too, say "url.img"
B) use grep(<grep-pattern>, df$url.img) to identify the rows of
"patt.url" you want to assemble.
Perhaps:
df[ grep("\\$IMAGE\\_ID\\$", df$url.img), "patt.url"]
url
http://www.url.com/image.jpg
http://www.blah.com/image.gif
Using something like > gsub(,image,pattern) doesn't work
because it only takes uses the first entry in "pattern" as the
replacement
for all "image" entries:
url
http://www.url.com/image.jpg
www.url.com/image.jpg
Please help.
Thanks.
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