Peng, If the answer were as simple as you suggest, I would expect that gee would automatically produce the p values. Since gee does not produce the values, I fear that the computation may be more complex, or perhaps computing p values from gee may be controversial. Do you know which, if either of my speculations is true? Thank you, John
John David Sorkin M.D., Ph.D. Chief, Biostatistics and Informatics University of Maryland School of Medicine Division of Gerontology Baltimore VA Medical Center 10 North Greene Street GRECC (BT/18/GR) Baltimore, MD 21201-1524 (Phone) 410-605-7119 (Fax) 410-605-7913 (Please call phone number above prior to faxing)>>> "Peng, C" <cpeng....@gmail.com> 9/10/2010 8:06 AM >>> There are two z-scores reported in the summary: Naive z and Robust z. pvalue=2*min(pnorm(z-score), 1-pnorm(z-score)) # two-sided test -- View this message in context: http://r.789695.n4.nabble.com/gee-p-values-tp2533835p2534302.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Confidentiality Statement: This email message, including any attachments, is for th...{{dropped:6}} ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
