Have you tried the 'sos' package?

install.packages('sos') # if not already installed
library(sos)
cr <- ???'constrained regression' # found 149 matches
summary(cr) # in 69 packages
cr # opens a table in a browser listing all 169 matches with links to the help pages


However, I agree with Ravi Varadhan: I'd want to understand the physical mechanism generating the data. If each is, for example, a proportion, then I'd want to use logistic regression, possible after some approximate logistic transformation of X1 and X2 that prevents logit(X) from going to +/-Inf. This is a different model, but it achieves the need to avoid predictions of Y going outside the range (0, 1).


      Spencer


On 10/31/2010 9:01 AM, David Winsemius wrote:

On Oct 31, 2010, at 2:44 AM, Jim Silverton wrote:

Hello everyone,
I have 3 variables Y, X1 and X2. Each variables lies between 0 and 1. I want
to do a constrained regression such that a>0 and (1-a) >0

for the model:

Y = a*X1 + (1-a)*X2


It would not accomplish the constraint that a > 0 but you could accomplish the other constraint within an lm fit:

X3 <- X1-X2
lm(Y ~ X3 + offset(X2) )

Since beta1 is for the model Y ~ 1 + beta1(X1- X2) + 1*X2)
                             Y ~ intercept + beta1*X1 + (1 -beta1)*X2

... so beta1 is a.

In the case beta < 0 then I suppose a would be assigned 0. This might be accomplished within an iterative calculation framework by a large penalization for negative values. In a reply (1) to a question by Carlos Alzola in 2008 on rhalp, Berwin Turlach offered a solution to a similar problem ( sum(coef) == 1 AND coef non-negative). Modifying his code to incorporate the above strategy (and choosing two variables for which parameter values might be inside the constraint boundaries) we get:

library(MASS)   ## to access the Boston data
designmat <- model.matrix(medv~I(age-lstat) +offset(lstat), data=Boston)
  Dmat <-crossprod(designmat, designmat); dvec <- crossprod(designmat,
  Boston$medv)
  Amat <- cbind(1, diag(NROW(Dmat)))
  bvec <- c(1,rep(0,NROW(Dmat)))
  meq <- 1
library(quadprog)
  res <- solve.QP(Dmat, dvec, Amat, bvec, meq)

> zapsmall(res$solution)
[1] 0.686547 0.313453

Turlach specifically advised against any interpretation of this particular result which was only contructed to demonstrate the mathematical mechanics.


I tried the help on the constrained regression in R but I concede that it
was not helpful.

I must not have that package installed because I got nothing that appeared to be useful with ??"constrained regression" .


David Winsemius, MD
West Hartford, CT

1) http://finzi.psych.upenn.edu/Rhelp10/2008-March/155990.html

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Spencer Graves, PE, PhD
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