Bill -
An excellent point, especially if you're concerned
about efficiency:
Y = list(sqrt,sin,function(u)u/2)
Ybar0 = function(u)mean(sapply(Y,function(fun)fun(u)))
Ybar1 = function(u) rowMeans(sapply(Y, function(fun) fun(u)))
system.time(one <- Vectorize(Ybar0)(seq(0,1,length=10000)))
user system elapsed
1.324 0.000 1.323
system.time(two <- Ybar1(seq(0,1,length=10000)))
user system elapsed
0.004 0.000 0.002
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Wed, 17 Nov 2010, bill.venab...@csiro.au wrote:
Another approach would be
Y <- list(sqrt, sin, function(u) u/2)
Ybar <- function(u) rowMeans(sapply(Y, function(fun) fun(u)))
integrate(Ybar, 0, 1)
0.4587882 with absolute error < 5.6e-05
i.e. make the function vectorized directly.
Note, however, that if you had
Y[[4]] <- function(u) 1
you would need to be careful and use something like
Y[[4]] <- function(u) rep(1, length(u))
or indeed
Y[[4]] <- Vectorize(function(u) 1)
for the process to work.
Bill Venables.
-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Phil Spector
Sent: Wednesday, 17 November 2010 10:24 AM
To: Eduardo de Oliveira Horta
Cc: r-help@r-project.org
Subject: Re: [R] Vectors out of lists?
Eduardo -
Thanks for the reproducible example!
Y<-list()
Y[[1]]<-function(u) sqrt(u)
Y[[2]]<-function(u) sin(u)
Y[[3]]<-function(u) 1/2*u
Ybar = function(u)mean(sapply(Y,function(fun)fun(u)))
Since integrate requires a function which accepts a vector
and returns a vector, we'd need to use Vectorize() before
trying to integrate:
integrate(Vectorize(Ybar),0,1)
0.4587882 with absolute error < 5.6e-05
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Tue, 16 Nov 2010, Eduardo de Oliveira Horta wrote:
Thanks, guys... but it seems these suggestions won't work.
Let me try to be more specific with a simple example:
Y<-list()
Y[[1]]<-function(u) sqrt(u)
Y[[2]]<-function(u) sin(u)
Y[[3]]<-function(u) 1/2*u
I wanted something equivalent to
Ybar<-function(u){
1/3*(Y[[1]](u) + Y[[2]](u) + Y[[3]](u))
}
but with arbitrary length(Y) and without using any loops. Also, I can't allow
for discretization, since I must be able to evaluate Ybar at any u, as I'm
going to integrate it with the function "integrate".
Thanks again,
Eduardo Horta
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