Dear Sir,
Sorry to bother you again. Sir, the R code provided by you gives me following
output.
> yy <- lapply(c(257, 520, 110), seq, to=0, by=-100)
> yy
[[1]]
[1] 257 157 57
[[2]]
[1] 520 420 320 220 120 20
[[3]]
[1] 110 10
The biggest constraint for me is here as an example I have taken only three
cases i.e. c(257, 520, 110), however in reality I will be dealing with no of
cases and that number is unknown. But your code will certainly generate me the
required numbers. In above case for doing further calculations, I can define
say
yy1 = as.numeric(yy[[1]])
yy2 = as.numeric(yy[2]])
yy3 = as.numeric(yy[[3]])
But when the number of cases are unknown, perhaps this is not the practical way
of me defining individually. So is there any way that I can have all the
sequence numbers generated can be accommodated in a single dataframe. I
sincerely apologize for disturbing you Sir and hope I am able to put up my
problem in a proper manner.
Regards
Vincy Pyne
--- On Thu, 12/9/10, Jan van der Laan <rh...@eoos.dds.nl> wrote:
From: Jan van der Laan <rh...@eoos.dds.nl>
Subject: Re: [R] Sequence generation in a table
To: r-help@r-project.org, vincy_p...@yahoo.ca
Received: Thursday, December 9, 2010, 10:57 AM
Vincy,
I suppose the following does what you want. yy is now a list which allows for
differing lengths of the vectors.
> yy <- lapply(c(257, 520, 110), seq, to=0, by=-100)
> yy[[1]]
[1] 257 157 57
> yy[[2]]
[1] 520 420 320 220 120 20
Regards,
Jan
On 9-12-2010 11:40, Vincy Pyne wrote:
> c(257, 520, 110)
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