Tianchan, why aren't you just using
col_no <- cut(r,c(0,2,4,6,8,10,100))
levels(col_no) <- c("<2%","2-4%","4-6%","6-8%","8-10%",">10%")
?
Your use of as.numeric() is nonsensical; check step by step what is
happening with that.
Hth,
Gerrit
On Tue, 14 Dec 2010, Tianchan Niu wrote:
Dear all,
I would like to use cut() to make numerics to factors, the sample codes are as follows. However, the
result is not what I want, since r[3] = 9 should be in the interval of "8-10%" rather than
"2-4%". Maybe cut() is not the right function to use for my situation. Please help. > r
<- c(1,1,9,1,1,1)
col_no <- as.factor(as.numeric(cut(r,c(0,2,4,6,8,10,100))))
levels(col_no) <- c("<2%","2-4%","4-6%","6-8%","8-10%",">10%")
col_no
[1] <2% <2% 2-4% <2% <2% <2%
Levels: <2% 2-4% 4-6% 6-8% 8-10% >10%Thanks,
Tianchan
Best regards -- Gerrit
Best regards -- Gerrit Eichner
Viele Grüße -- Gerrit
Viele Grüße -- Gerrit Eichner
Viele Grüße -- GE
Freundliche Grüße -- Gerrit Eichner
Freundliche Grüße -- GE
Grüße -- Gerrit
Grüße -- Gerrit Eichner
Grüße -- GE
Gruß -- G
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