Dear sir,
Thanks a lot for the solution.
It was such a simple solution, but people like me close their minds and don't
think of data.frame as a whole and keep on thinking about vector elements only.
I also almost got the solution when I tried
qq = unique(pp)
(qq <- sub(" .*","", qq)) but this was giving me only first element of qq.
so I reversed the way I had defined paste command and saved it in some otehr
name and again applied above command and I got the element. But I know that is
not how good programs are written.
Regards
Vincy
--- On Sat, 3/12/11, Petr Savicky <savi...@praha1.ff.cuni.cz> wrote:
From: Petr Savicky <savi...@praha1.ff.cuni.cz>
Subject: Re: [R] Identifying unique pairs
To: r-help@r-project.org
Received: Saturday, March 12, 2011, 2:10 PM
On Sat, Mar 12, 2011 at 03:20:01AM -0800, Vincy Pyne wrote:
> Dear R helpers
>
> Suppose I have a data frame as given below
>
> mydat = data.frame(x = c(1,1,1, 2, 2, 2, 2, 2, 5, 5, 6), y = c(10, 10, 10, 8,
> 8, 8, 7, 7, 2, 2, 4))
>
[...]
>
> unique(mydat$x) will give me 1, 2, 5, 6? i.e. 4 values and
> unique(mydat$y) will give me 10, 8, 7, 2, 4.
>
> What I need is a data frame where I will get a vector (say) x_new as (1, 2,
> 2, 5, 6) and corresponding y_new as (10, 8, 7, 2, 4). I need to use these two
> vectors viz. x_new and y_new seperately for further processing. They may be
> under same data frame say mydat_new but I should be able to access them as
> mydat_new$x_new and similarly for y.
>
> I tried following way.
>
> pp = paste(mydat$x, mydat$y)
>
> pp = > pp
> ?[1] "1 10" "1 10" "1 10" "2 8"? "2 8"? "2 8"? "2 7"? "2 7"? "5 2"? "5 2"? "6
> 4"
>
> qq = unique(pp)
>
> > qq
> [1] "1 10" "2 8"? "2 7"? "5 2"? "6 4"
Hi.
If i understand you correctly, then the solution is easy, since function
unique() can handle also rows of a data frame. Is the following, what
you expect?
unique(mydat)
x y
1 1 10
4 2 8
7 2 7
9 5 2
11 6 4
Petr Savicky.
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