Try this:
l <- list(matrix(rnorm(9), 3), matrix(rnorm(9), 3), matrix(rnorm(9), 3))
Reduce('+', l) / length(l)
On Tue, Mar 15, 2011 at 5:17 PM, hihi <[email protected]> wrote:
> Hi All,
> is there any effiective and dense/compact method to calculate the mean of a
> list of - of course coincident - matrices on an element by element basis?
> The resulting matrix' [i, j]-th element is the mean of the list's matrices'
> [i, j]-th elements respectively...
> Iterating by for statement is quite straightforward, but I am seeking for a
> more elegant solution, and my attempt with the apply family of functions did
> not work.
>
> Thank you,
> by
> Peter
>
> ______________________________________________
> [email protected] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
[[alternative HTML version deleted]]
______________________________________________
[email protected] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
