Numeric underflow. Try qr.solve(a)
Allan
On 16/03/11 15:28, Feng Li wrote:
Dear R,
If I have remembered correctly, a square matrix is singular if and only if
its determinant is zero. I am a bit confused by the following code error.
Can someone give me a hint?
a<- matrix(c(1e20,1e2,1e3,1e3),2)
det(a)
[1] 1e+23
solve(a)
Error in solve.default(a) :
system is computationally singular: reciprocal condition number = 1e-17
Thanks in advance!
Feng
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