Dear all, According to the post I was trying:
factorA = c(2,2,3,3,4,4,3,4,2,2) levels(factorA <- c("lv1","lv2","lv3") ) But this returns NULL and doesn't change factor names. Actually, my factor is included in a data.frame, so I also tried: levels(df$factorA)[levels(df$factorA)=="2"] <- "lv1" Also levels(df$factorA)[levels(df$factorA)==2] <- "lv1" levels(df$factorA)[levels(df$factorA)=="3"] <- "lv2" levels(df$factorA)[levels(df$factorA)=="4"] <- "lv3" then I type table(df$factorA) and it doesn't work either. After attach(df), I tried also this for(i in 1:10) { if(factor(factorA)[i]==2) factorA[i]="lv2" else {; if(factor(factorA)[i]==3) factorA[i]="lv3" else {; factorA[i]= "lv4"}}}} Any help would be appreciated. Thanks, u...@host.com -- View this message in context: http://r.789695.n4.nabble.com/factor-with-numeric-names-tp882535p3405247.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.