Walter -
Since your codes represent numbers, you could use something like
this:
chk = as.numeric((hh.sub$HHFAMINC)
hh.sub$CS_FAMINC = cut(chk,c(-10,0,5,10,15,17,18),labels=c(0,1:5))
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Wed, 6 Apr 2011, Walter Anderson wrote:
I have cobbled together the following logic. It works but is very slow.
I'm sure that there must be a better r-specific way to implement this kind of
thing, but have been unable to find/understand one. Any help would be
appreciated.
hh.sub <- households[c("HOUSEID","HHFAMINC")]
for (indx in 1:length(hh.sub$HOUSEID)) {
if ((hh.sub$HHFAMINC[indx] == '01') | (hh.sub$HHFAMINC[indx] == '02') |
(hh.sub$HHFAMINC[indx] == '03') | (hh.sub$HHFAMINC[indx] == '04') |
(hh.sub$HHFAMINC[indx] == '05'))
hh.sub$CS_FAMINC[indx] <- 1 # Less than $25,000
if ((hh.sub$HHFAMINC[indx] == '06') | (hh.sub$HHFAMINC[indx] == '07') |
(hh.sub$HHFAMINC[indx] == '08') | (hh.sub$HHFAMINC[indx] == '09') |
(hh.sub$HHFAMINC[indx] == '10'))
hh.sub$CS_FAMINC[indx] <- 2 # $25,000 to $50,000
if ((hh.sub$HHFAMINC[indx] == '11') | (hh.sub$HHFAMINC[indx] == '12') |
(hh.sub$HHFAMINC[indx] == '13') | (hh.sub$HHFAMINC[indx] == '14') |
(hh.sub$HHFAMINC[indx] == '15'))
hh.sub$CS_FAMINC[indx] <- 3 # $50,000 to $75,000
if ((hh.sub$HHFAMINC[indx] == '16') | (hh.sub$HHFAMINC[indx] == '17'))
hh.sub$CS_FAMINC[indx] <- 4 # $75,000 to $100,000
if ((hh.sub$HHFAMINC[indx] == '18'))
hh.sub$CS_FAMINC[indx] <- 5 # More than $100,000
if ((hh.sub$HHFAMINC[indx] == '-7') | (hh.sub$HHFAMINC[indx] == '-8') |
(hh.sub$HHFAMINC[indx] == '-9'))
hh.sub$CS_FAMINC[indx] = 0
}
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
