probably expand.grid(), e.g., expand.grid(rep(list(0:6), 3))
I hope it helps. Best, Dimitris On 4/21/2011 9:28 PM, Kehl Dániel wrote:
Dear all, is there an easy way to get all possible combinations (?) with replacement. If n=6, k=3, i want something like 0 0 6 0 5 1 0 4 2 0 3 3 0 2 4 . . . 5 0 1 5 1 0 6 0 0 I tried to look at combn() but I could not get this done with it. Thank you in advance: Daniel ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
-- Dimitris Rizopoulos Assistant Professor Department of Biostatistics Erasmus University Medical Center Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands Tel: +31/(0)10/7043478 Fax: +31/(0)10/7043014 Web: http://www.erasmusmc.nl/biostatistiek/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
