On 29/04/2011 9:34 PM, Miao wrote:
Thanks Duncan for clarifying this. I'm pretty a newbie to such type of
characters and special characters. In R's gsub() what regular
expressions shall I use to handle all these situations?
I don't know. This might work:
gsub("[\x01-\x1f\x7f-\xff]", "", x)
(i.e. the range from character 1 to character 31, and 127 to 255) but I
don't know if our regular expression matcher will accept those characters.
Duncan Murdoch
On Fri, Apr 29, 2011 at 6:07 PM, Duncan Murdoch
<[email protected] <mailto:[email protected]>> wrote:
On 29/04/2011 7:41 PM, Miao wrote:
Hello,
Can anyone help on gsub() in R? I have a string like something
below, and
wanted to delete all the strings with leading backslash,
including "\xa0On",
"\023, "\xab", and many others. How should I write a regular
expression
pattern in gsub()? I don't care how many characters following
backslash.
If those are R strings, none of them contain a backslash. In R, a
backslash would always be printed as \\.
\x is the introduction to a hexadecimal encoding for a character;
the next two characters show the hex digits. So your first string
contains a single character \xa0, the third one contains \xab, and
so on.
The \023 is an octal encoding for a single character.
Duncan Murdoch
txt<- "Is This Thing\xa0On? http://bit.ly/jAbKem wait \023 for
people \xab
and be patient :"
Thanks in advance,
Miao
[[alternative HTML version deleted]]
______________________________________________
[email protected] <mailto:[email protected]> mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
proceed everyday
______________________________________________
[email protected] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
