Try this: sapply(lapply(strsplit(l, ":"), strsplit, ","), function(x)structure(lapply(x[2], as.numeric), .Names = x[1]))
On Thu, Jun 23, 2011 at 11:39 AM, Michael Pearmain <michael.pearm...@gmail.com> wrote: > Hi All, > > I've been given a data file of the form: > 1: 3,4,5,6 > 2:1,2,3 > 43: 5,7,8,9,5 > > and i want to read this data in as a list to create the form: > (guessing final look) > my.list > [[1]] > [1] 3 4 5 6 > > [[2]] > [1] 1 2 3 > > [[43]] > [1] 5 7 8 9 5 > > I can get to a stage using scan: > scan("my.data", what = character(0), quiet = TRUE) > to load > [1] "1: 3,4,5,6" > [2] "2:1,2,3" > [3] "43: 5,7,8,9,5" > > but im not sure on how next to proceed to arrange this into a list form, can > anyone offer some advise? > > Thanks in advance > > Mike > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.