On 2011-06-24 09:52, Salih Tuna wrote:
Hi guys,
let's assume i have the following
1
x = 2
6
5
1 4
y = 3 5
8 10
i want the code to report back 1, 2 and 5 from x.
Basically it shopuld check whether each elements of x falls in the range of
each row of x. 1 and 2 falls in between 1-4 and 5 falls in between 3-5.
I do this with two for loops but in the case of very large list, it takes
ages.
Probably not faster, but try:
x <- c(1,2,6,5)
y <- matrix( c(1,3,8,4,5,10), 3, 2 )
ok <- vector( 'logical', length(x) )
for( i in seq_along(x) ) ok[i] <- any( apply(y - x[i], 1, prod) <= 0 )
x[ok]
Peter Ehlers
best,
salih
On Fri, Jun 24, 2011 at 4:12 PM, Dennis Murphy<djmu...@gmail.com> wrote:
Hi:
That leaves open several possibilities. Could you please supply a
small, reproducible example (i.e., one that someone can copy and paste
into an R session) that illustrates the problem along with the
solution you expect?
TIA,
Dennis
On Fri, Jun 24, 2011 at 2:30 AM, Salih Tuna<saliht...@gmail.com> wrote:
Hi Dimitris,
Thanks for your reply. But this is not exactly what i am after. I want to
find the probes that falls into certain regions. In your solution it will
ignore the second probe if it falls into the same region as the first
one.
Is there any vector trickb uilt in R to find whether probes fall into
certain regions?
best,
salih
On Fri, Jun 24, 2011 at 10:23 AM, Dimitris Rizopoulos<
d.rizopou...@erasmusmc.nl> wrote:
One approach is the following:
x<- rnorm(5)
y<- matrix(rnorm(5*2), 5, 2)
check<- y - x
check[, 1] * check[, 2]< 0
I hope it helps.
Best,
Dimitris
On 6/24/2011 10:57 AM, Salih Tuna wrote:
Hi All,
What is the fastest way of finding if any members of vector x fall in
the
range of the rows of matrix y?
I do not want to use two for loops as this will take forever.
Any help will be appreciated,
best,
salih
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