On Jun 25, 2011, at 12:49 PM, Håvard Wahl Kongsgård wrote:
Hi, this seems like a strange question, but in R is there a function
that
can handle vectors containing factors inside lists/tuples?
Yes, A very strange question, indeed ... since dataframes are lists
that commonly contain vectors of factors and you should have
encountered them very early in your self-study of R. The number of
functions that operate on dataframes is large. Are you very early in
efforts at learning R? Have you read the Posting Guide? (You're still
posting html format.)
?factor
?list
?dataframe
Or is there some
other approach/functions I can use?
Like for example
V1
"{"Harry","Brown")"
"{"Brown","Harry")"
Is that an example that would make sense in some other language?
(Opening curly-brace and closing paren makes no sense in R or for
that matter in what small amount I know of set theory.) Since your
example makes no sense, it remains possible that you're looking for
set operations:
?union
I want to use these variables in a machine learning setting, And
don't want
to convert these into multiple vectors, given share number of factors.
Lists (of which dataframes are one specific example) are the usual
method of handling structures of arbitrary structure (including
factors). 'lapply' is the usual choice for repetitive application of a
function to elements of lists. The is also 'rapply' for recursive
application
> lapply(list(factor(letters[1:10]), list(c(1:10), c(20:30) ),
letters[10:20]), length)
[[1]]
[1] 10
[[2]] # second element is a list with two members
[1] 2 # lapply() only works with the first 'level' of a list
[[3]]
[1] 11
> rapply(list(factor(letters[1:10]), list(c(1:10), c(20:30) ),
letters[10:20]), length)
[1] 10 10 11 11
> lapply(list(factor(letters[1:10]), list(c(1:10), c(20:30) ),
letters[10:20]), class)
[[1]]
[1] "factor"
[[2]]
[1] "list"
[[3]]
[1] "character"
--
David Winsemius, MD
West Hartford, CT
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