On Jul 17, 2011, at 5:29 PM, jim holtman wrote:
try this:
z <- c(-1.4,0.5,4.7)
(z >= -3) & (z <= 3)
[1] TRUE TRUE FALSE
Another way:
> findInterval(z, c(-3,3)) == 1
[1] TRUE TRUE FALSE
> z=c(-50,-1.4,0.5,4.7)
And just to prove to myself that it behaves as I expect with values
below -3:
> findInterval(z, c(-3,3)) == 1
[1] FALSE TRUE TRUE FALSE
You may need to check that the method you choose behaves as you expect
at the extremes. findInterval behaves the same way as cut() does in
its default mode. The maximum value matches but the minimum value does
not:
> z=c(-50,-1.4,0.5,4.7, 3, -3)
> findInterval(z, c(-3,3)) == 1
[1] FALSE TRUE TRUE FALSE FALSE TRUE
> cut(seq(-4, 4, by=1), breaks=c(-3,3))
[1] <NA> <NA> (-3,3] (-3,3] (-3,3] (-3,3] (-3,3] (-3,3] <NA>
Levels: (-3,3]
Jim's method lets you determine if you want inclusivity at both or
either end.
--
David.
On Sun, Jul 17, 2011 at 10:54 AM, Manuel K. <b8220...@klzlk.com>
wrote:
Hi all,
I have an interval (e.g [-3,3]) and a numeric vector z
(-1.4,0.5,4.7). How
can I test whether an element in z lies between between -3,3? I
particularly
need a TRUE/FALSE response.
Thanks
Manuel
--
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--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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David Winsemius, MD
West Hartford, CT
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