Ah, now we're getting somewhere. Think how easy this would be if you'd provided this information initially.
On Fri, Jul 29, 2011 at 11:11 AM, <[email protected]> wrote: > Ø data=read.table("http://statcourse.com/research/boston.csv";, , sep=",", > header = TRUE) > Ø library(rpart) > Ø fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) > Please: Show me the tree. > Mark Well, your rpart() statement won't run, so obviously you can't see the tree. There's no data argument, and the variable names don't match the column headers in the data you provided. Here's a revised version, that prints and plots the tree, and predicts some test data. # corrected rpart(), guessing at what you meant markdata <- read.table("http://statcourse.com/research/boston.csv";, , sep=",", header = TRUE) fit <- rpart (MEDV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PTRATIO+B+LSTAT, data=markdata) # two ways of looking at the complete tree fit plot(fit) text(fit) # predicting a few values mark.subsample <- markdata[1:5,] predict(fit, mark.subsample, type="vector") If this is your actual code, your problem was far more basic than plotting and predicting. Sharing your error messages would have been a good start. Sarah -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
