You defined temp as a vector:

> temp <- vector(mode="numeric", length = vl)

but you try to extract from it as if it was a 2d object:

colA <- temp[,compareA]

Maybe you meant to use temp1 instead? More meaningful variable names might
help avoid such mistakes.

On Wed, Aug 3, 2011 at 6:14 PM, Matt Curcio <[email protected]>wrote:

> Greetings all,
> I am getting an error message that is stifling me.
> Any ideas?
>
> > ## Define Directories ##
> > load_from <- "/home/mcc/Dropbox/abrodsky/kegg_combine_data/"
> > save_to <- "/home/mcc/Dropbox/abrodsky/ttest_results/"
> >
> > ###############################
> > ## Define Columns To Compare ##
> > compareA <- "log_b_rich"
> > compareB <- "Fc_cdt_rich_tot"
> >
> > ################################
> > ## Collect Files To Compare ##
> > setwd(load_from)
> > files_to_test <- list.files(pattern = "combine.kegg")
> >
> > ##########################
> > ## Initialize Variables ##
> > vl <- length(files_to_test)
> > temp <- vector(mode="numeric", length = vl)
> > colA <- vector(mode="numeric", length = vl)
> > colB <- vector(mode="numeric", length = vl)
> > tt <- vector(mode="numeric", length = vl)
> >
> >
> > ########################
> > ## Calculate P-values ##
> > for (i in 1:3){
> +    temp1 <- read.table(files_to_test[i], header=TRUE, sep=" ")
> +    numrows <- nrow(temp1)
> +    tt_pvalue <- matrix(data=temp, nrow=numrows, ncol=vl)
> +    colA <- temp[,compareA]
> +    colB <- temp[,compareB]
> +    tt <- t.test(colA, colB, var.equal=TRUE)
> +    tt_pvalue <- tt$p.value
> + }
> Error in temp[, compareA] : incorrect number of dimensions
>
> --
>
>
> Matt Curcio
> M: 401-316-5358
> E: [email protected]
>
> ______________________________________________
> [email protected] mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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