Just a clarification: I can't get round to work as I first expected so if you want to do bins by 100's you'd probably want:
split(a, cut(a$spending, breaks = (0:5)*100)) Michael On Mon, Dec 5, 2011 at 3:41 PM, R. Michael Weylandt <michael.weyla...@gmail.com> wrote: > I'd so something like > > split(a, a$spending) > > and you can include a round(a$spending, -2) or something similar if > you want to group by the 100's. > > Michael > > On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith <diviya.sm...@gmail.com> wrote: >> Hello there, >> >> I have a matrix with some data and I want to split this matrix based on the >> values in one column. Is there a quick way of doing this? I have looked at >> cut but I am not sure how to exactly use it? >> for example: >> >> I would like to split the matrix "a" based on the spending such that the >> data is binned groups [0..99],[100..199]...and so on. >> >> a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), >> age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 250, 400, 450)) >> >> Expected output - >> bin[1] <- c(10, 60) >> bin[2] <- c(110, 200, 250) >> bin[3] <- c(400, 450) >> >> NOTE that the number of data points in each bin is not the same and the >> empty bins are removed (since there are no points between [199..299], >> bin[3] starts at 400. >> >> Any help would be most appreciated. Thank you in advance. >> >> Diviya >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.