Hi, You can do that even without apply():
v.v<-seq(10,20, by=0.1) y<-v.v^2 But if you want it with apply... apply(as.matrix(v.v), 1, function(x) x^2) Regards, Carlos Ortega www.qualityexcellence.es 2012/1/31 arunkumar1111 <akpbond...@gmail.com> > Hi > > I have a function > > y= x^2 > > min =10 > max=20 > increment=0.1 > > I want to find the value of y for the value of x between min and max by > step > increment. > > how to get the values using apply function instead of for loop > > ----- > Thanks in Advance > Arun > -- > View this message in context: > http://r.789695.n4.nabble.com/Help-required-in-using-apply-instead-of-for-loop-tp4344350p4344350.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
