Hello,
I can get the median for each factor, but I'd like another column to go
with each factor. The nm column is a long name for the lvls column. So
unique work except for the order can get messed up.
Example:
x =
data.frame(val=1:10,lvls=c('cat2',rep("cat1",4),rep("cat2",4),'cat1'),nm=c('longname2',rep("longname1",4),rep("longname2",4),'longname1'))
x
val lvls nm
1 1 cat2 longname2
2 2 cat1 longname1
3 3 cat1 longname1
4 4 cat1 longname1
5 5 cat1 longname1
6 6 cat2 longname2
7 7 cat2 longname2
8 8 cat2 longname2
9 9 cat2 longname2
10 10 cat1 longname1
unique doesn't work in data.frame:
mdn = do.call(rbind,lapply(split(x[,1], x[,2]), median))
data.frame(mdn,ln=as.character(unique(x[,3])))
mdn ln
cat1 4 longname2
cat2 7 longname1
I want:
mdn ln
cat1 4 longname1
cat2 7 longname2
Thank you very much!
PS - looking for simple'ish solutions. I know I can do it with loops and
merges, but is there an option I am not using here?
Ben
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