No, it won't give the same result. If you load packages or have hidden variables / environments, they'll remain in the session or if you change global options they'll stay. It's a somewhat frequently asked question, but there's no way to get a "factory fresh" session without restarting R. You can get pretty close though with
##################################### ####### rm(list = ls(all.names = TRUE)) # will get hidden (.xyz) variables ##################################### and detach() applied to all of the package namespaces. You'll still have some registered methods and whatnot around, but this will do most of the cleanup. Michael On Mon, Mar 5, 2012 at 6:29 PM, Wet Bell Diver <wetbelldi...@gmail.com> wrote: > R-2.14.2, Win7 x64 > > Dear list, > > I have the habit of including rm(list=ls()) at the top of most of my > scripts. However, I wonder whether rm(list=ls()) gives the exact same result > as closing R and starting again fresh. > In other words, is it possible that there will be differences on how a > script runs under a fresh start of R versus when I "only" use rm(list=ls()) > , or should both approaches give the exact same starting situation every > time? > > Thanks, > Peter > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.