No idea what a "mean median histogram" is but you may wish to check out ?tapply or library(plyr), both of which are designed for this split-apply-combine paradigm.
Michael On Tue, Mar 27, 2012 at 12:51 AM, arunkumar1111 <akpbond...@gmail.com> wrote: > Hi > > I have records like like this > > X1 X2 State > 34 72 state1 > 9 63 state1 > 49 31 state1 > 60 34 state1 > 80 73 state1 > 60 20 state2 > 59 87 state2 > 88 20 state2 > 71 66 state2 > 65 56 state2 > 59 16 state1 > 60 100 state2 > > > I want to get the summarize value like mean median histogram for X1 and X2 > based on state. I'm using FOR loop for this. Is there any method to remove > for loop and use apply or any alternatives > > > ----- > Thanks in Advance > Arun > -- > View this message in context: > http://r.789695.n4.nabble.com/help-in-replacing-for-llop-tp4507939p4507939.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.