Consider also the following:
a <- 1.2
b <- 1.0
> (a-b)%%.1
[1] 0.1
> (a-b)%/%.1
[1] 1
> .2%%.1
[1] 0
> .2%/%.1
[1] 2
This performs as described on "?%/%". In particular, the second
paragraph under "Value":
'%%' indicates 'x mod y' and '%/%' indicates integer division. It
is guaranteed that 'x == (x %% y) + y * ( x %/% y )' (up to
rounding error) unless 'y == 0' where the result is 'NA_integer_'
or 'NaN' (depending on the 'typeof' of the arguments). See <URL:
http://en.wikipedia.org/wiki/Modulo_operation> for the rationale.
hope this helps.
Spencer
jim holtman wrote:
> FAQ 7.31
>
> a-b != 0.2
>
>
>> a <- 1.2
>>
>> b <- 1.0
>>
>> a-b-.2
>>
> [1] -5.551115e-17
>
>
>
>
> On 3/31/08, Lo, Ken <[EMAIL PROTECTED]> wrote:
>
>> Dear all,
>>
>>
>>
>> I have come across a strange behavior of the %/% operator, and I wasn't
>> sure if this was intended.
>>
>>
>>
>> i.e.
>>
>> a <- 1.2
>>
>> b <- 1.0
>>
>> (a-b) %/% 0.1 results in 1?
>>
>> Whereas
>>
>> 0.2 %/% 0.1 results in 2.
>>
>>
>>
>> Am I missing something obvious here? It seems to be consistent up to R
>> 2.6.0 running in WinXP (haven't upgraded yet).
>>
>>
>>
>> Best,
>>
>>
>>
>> Ken
>>
>>
>>
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>
>
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