Dimitris, Petra, Thank you! aggregate() is my lesson for today, not melt() | cast()
Really appreciate the super fast help, Karl On 07/05/12 12:09, Dimitris Rizopoulos wrote:
you could try aggregate(), e.g., my.df <- data.frame(pathway = c(rep("pw.A", 2), rep("pw.B", 3), rep("pw.C", 1)), cond.one = c(0.5, NA, 0.4, NA, NA, NA), cond.two = c(NA, 0.6, NA, 0.9, NA, 0.2), cond.three = c(NA, NA, NA, NA, 0.1, NA)) aggregate(my.df[-1], my.df['pathway'], sum, na.rm = TRUE) or sum. <- function(x) if (all(is.na(x))) NA else sum(x, na.rm = TRUE) aggregate(my.df[-1], my.df['pathway'], sum.) I hope it helps. Best, Dimitris On 5/7/2012 11:50 AM, Karl Brand wrote:Esteemed UseRs, This must be embarrassingly trivial to achieve with e.g., melt() and cast(): deduplicating records ("pw.X" in example) for a given set of responses ("cond.Y" in example). Hopefully the runnable example shows clearly what i have and what i'm trying to convert it to. But i'm just not getting it, ?cast that is! So i'd really appreciate some ones patience to clarify this, using the reshape package, or any other approach. With sincere thanks in advance, Karl ## Runnable example ## The data.frame i have: library("reshape") my.df <- data.frame(pathway = c(rep("pw.A", 2), rep("pw.B", 3), rep("pw.C", 1)), cond.one = c(0.5, NA, 0.4, NA, NA, NA), cond.two = c(NA, 0.6, NA, 0.9, NA, 0.2), cond.three = c(NA, NA, NA, NA, 0.1, NA)) my.df ## The data fram i want: wanted.df <- data.frame(pathway = c("pw.A", "pw.B", "pw.C"), cond.one = c(0.5, 0.4, NA), cond.two = c(0.6, 0.9, 0.2), cond.three = c(NA, 0.1, NA)) wanted.df
-- Karl Brand Dept of Cardiology and Dept of Bioinformatics Erasmus MC Dr Molewaterplein 50 3015 GE Rotterdam T +31 (0)10 703 2460 |M +31 (0)642 777 268 |F +31 (0)10 704 4161 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
