On 07/09/2012 2:12 PM, David Romano wrote:
Hi folks,Suppose I create the character vector charvec by > charvec<-c("a1.b1","a2.b2") > charvec [1] "a1.b1" "a2.b2" and then I use strsplit on charvec as follows: > splitlist<-strsplit(charvec,split=".",fixed=TRUE) > splitlist [[1]] [1] "a1" "b1" [[2]] [1] "a2" "b2" I was wondering whether there is already a function which can extract the "a" and "b" parts of the list splitlist; that is, that can return the same vectors as those created by c("a1","a2") and c("b1","b2").
sapply is the one that comes to mind: > sapply(splitlist, "[[", 1) [1] "a1" "a2" > sapply(splitlist, "[[", 2) [1] "b1" "b2" ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
