If they are already in decreasing order, you might be able to work something out like (untested):
cumsum(c(1, diff(x) < 0)) Cheers, Michael On Fri, Oct 12, 2012 at 8:05 AM, Henri-Paul Indiogine <[email protected]> wrote: > Greetings! > > I have the following vector already in decreasing order: > > 125, 124, 111, 108, 107, 107, 105, .... > > I want to find out the rank, so I do the following: > > rank(-x, ties.method="min") > > Then I get the following: > > 1, 2, 3, 4, 5, 5, 7, .... > > but that is not what I want. I want it to give: > > 1. ,2, 3, 4, 5 ,5, 6, .... > > There should be no "jumps" in the sequence. > > How would that be possible? > > Thanks, > Henri-Paul > > -- > Henri-Paul Indiogine > > Curriculum & Instruction > Texas A&M University > TutorFind Learning Centre > http://www.tutorfind.ca > > Email: [email protected] > Skype: hindiogine > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
