toDaySecond <- function(date.string, format.string='%d%b%Y:%T', tz='') {
d <- as.POSIXct(d, format=format.string, tz=tz)
sum(mapply(function(f, l) as.numeric(format(d, format=f)) * l,
c('%H', '%M', '%S'), c(3600, 60, 1)))
}
toDaySecond('04MAY2011:08:19:00')
Will calculate the second of the day. divide by 3600 to convert to hours.
On Tue, Oct 16, 2012 at 4:21 PM, Jeff Newmiller
<[email protected]> wrote:
> There are multiple ways. For lack of your example, I would suggest
> multiplying by 24.
>
> Please post the previous context of the thread if you must post from Nabble.
> ---------------------------------------------------------------------------
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>
> york8866 <[email protected]> wrote:
>
>>Thanks,
>>
>>The code gives the numbers in "days", how can I adjust the code to
>>directly
>>get the numbers in "hours"?
>>
>>I tried units but it did not work.
>>
>>Thanks1
>>
>>
>>
>>--
>>View this message in context:
>>http://r.789695.n4.nabble.com/time-extraction-and-normalization-tp4646275p4646298.html
>>Sent from the R help mailing list archive at Nabble.com.
>>
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>>and provide commented, minimal, self-contained, reproducible code.
>
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______________________________________________
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.