This works ok: > cox = coxph(surv ~ bucket*(today + accor + both) + activity, data = data) > fit = survfit(cox, newdata=data[1:100,])
but using strata leads to problems: > cox.s = coxph(surv ~ bucket*(today + accor + both) + strata(activity), > data = data) > fit.s = survfit(cox.s, newdata=data[1:100,]) Error in model.frame.default(data = data[1:100, ], formula = ~bucket + : number of variables != number of variable names Note that the following give rise to the same error: > fit.s = survfit(cox.s, newdata=data) Error in model.frame.default(data = data, formula = ~bucket + today + : number of variables != number of variable names but if I use data implicitly, all is working fine: > fit.s = survfit(cox.s) Any idea on how I could solve this? Best, and thank you, ge -- View this message in context: http://r.789695.n4.nabble.com/survfit-number-of-variables-number-of-variable-names-tp4649834.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
