Hi, Antti,
you should look at
?levels
(and particular its "Examples" section) to find out how to use
levels( X) <- c( "new1", ......., "newk")
to achieve what you want.
Regards -- Gerrit
On Thu, 17 Jan 2013, Antti Simola wrote:
Hi,
This is quite simple data manipulation task and I need help for it. I want to
make new factor variable that is an aggregation of an existing factor.
This works as I intended:
X[Y == "original label"] <- " new label"
How to make following work then (to make coding more convenient):
original.labels <- c("ol.1","ol.2","ol.3")
X[Y == original.labels] <- "new label"
Cheers,
Antti
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