> it lets you do: > > (a~b~c) = foo() Mistook. should be:
(a~b~c) %=% foo() because it defines the %=% operator. Barry ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
