Thanks Bert for your example.
I wouldn't say that I understand why everything happens the way it does, but at least I now know what happens!
I think I now need to use it and try around!

Ivan

--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
http://biogeosciences.u-bourgogne.fr/calandra

Le 30/01/13 18:44, Bert Gunter a écrit :
Because R can be interactive, I find that a little exploring through
the use of strategically placed browser() calls (?browser if you are
unfamiliar with this handy debugging tool) is often the fastest way to
solve little R puzzles like this.

For example, try this (in an R GUI):

f2 <- function(y,...){ browser(); list(...) }
f1 <- function(x,...){ browser(); f2(x,...) }

Now at the command line:

f1( x=1, z= 2:4)
## In the f1 browser  do ls() to see what's in the f1 environment
## and then do list(...) to see what's in the dots argument
## then issue the browser command  c  to continue
## and do the same in the f2 browser .

## then try:
f1( x=1, y= 2:4)  ## and
f1( 2:4)
f1( y=2:4) ## this will produce an error in f2
I think this help give you a better idea of what's going on (or
totally confuse?!).

-- Bert




On Wed, Jan 30, 2013 at 8:15 AM, Patrick Burns <pbu...@pburns.seanet.com> wrote:
There is now a blog post that attempts to
answer the question in the subject line:

http://www.burns-stat.com/the-three-dots-construct-in-r/

Pat

On 17/01/2013 14:36, Ivan Calandra wrote:
Dear users,

I'm trying to learn how to use the "...".

I have written a function (simplified here) that uses doBy::summaryBy():
# 'dat' is a data.frame from which the aggregation is computed
# 'vec_cat' is a integer vector defining which columns of the data.frame
should be use on the right side of the formula
# 'stat_fun' is the function that will be run to aggregate
stat.group <- function(dat, vec_cat, stat_fun){
      require(doBy)
      df <-

summaryBy(as.formula(paste0(".~",paste0(names(dat)[vec_cat],collapse="+"))),
data=dat, FUN=stat_fun)
      return(df)
}

Example, works fine:
my_data <- structure(list(cat = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L,
2L, 2L, 2L), .Label = c("A", "B"), class = "factor"), varnum =
c(-0.754816565434373,
-1.94101630973709, -0.102461836059522, -0.519952759645808,
-1.73772800855664,
-1.13939178585609, 0.522356715260142, -0.701428514907824,
1.45197576541159,
0.0844567413828095)), .Names = c("cat", "varnum"), row.names = c(NA,
-10L), class = "data.frame")
stat.group(dat=my_data, vec_cat=1, stat_fun=mean)


Now summaryBy() has an "..." argument and I would like to use it.
For example, I would like to be able to add the trim argument to my call
like this:
stat.group(dat=my_data, vec_cat=1, stat_fun=mean, trim=0.2)


I know I can do it using this "..." but I have no idea how to do it.
I've tried to search for it, but a search with "..." doesn't yield
interesting results!


Thank you in advance for your help!
Ivan

--
Patrick Burns
pbu...@pburns.seanet.com
twitter: @burnsstat @portfolioprobe
http://www.portfolioprobe.com/blog
http://www.burns-stat.com
(home of:
  'Impatient R'
  'The R Inferno'
  'Tao Te Programming')

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