> HI, > # > Pm2<-rbeta(1000, 0.2+1, 0.8+3) #obs4 > length(Pm2) > #[1] 1000 > > > Pn2<-rbeta(1000, 0.2, 0.8+4) > length(Pn2) > #[1] 1000 > Here, you are creating Pm2 or Pn2 from a single observation. > > In the code, it is creating 1000 values in total from the combination of > values from x, m, > Pm2<-rbeta(1000, 0.2+res2$x, 0.8+res2$m-res2$x) > length(Pm2) > #[1] 1000 > I dont' get it. I thought it should create 1000 randome samples from the > beta distribution for each combination of values of x and m and this is > what I wanted. So for the 4th observation x=1, m=4, y=0, n =4 the Fmm2, > Fnn2 should be consistent with the values of Fmm2, Fnn2 from the following > code. >
Pm2<-rbeta(1000, 0.2+1, 0.8+3) #obs4 Pn2<-rbeta(1000, 0.2, 0.8+4) Fm2<- ecdf(Pm2) Fn2<- ecdf(Pn2) Fmm2<-Fm2(1/4) Fnn2<-Fn2(0) Fmm2 #0.582 Fnn2 #0 > A.K. > > > > ----- Original Message ----- > From: Zjoanna <[hidden > email]<http://user/SendEmail.jtp?type=node&node=4659769&i=0>> > > To: [hidden email] <http://user/SendEmail.jtp?type=node&node=4659769&i=1> > Cc: > Sent: Tuesday, February 26, 2013 3:13 PM > Subject: Re: [R] cumulative sum by group and under some criteria > > Hi Arun > > I noticed that the values of Fmm, Fnn, and other corresponding variables > are not correct, for example, for the 4th obs after you run this code, > the > Fmm is 0.40, but if you use the x, m, y, n in the 4th row to calculate > them, the results are not consistent, same for the 5th obs. > > #check > # > Pm2<-rbeta(1000, 0.2+1, 0.8+3) #obs4 > Pn2<-rbeta(1000, 0.2, 0.8+4) > Fm2<- ecdf(Pm2) > Fn2<- ecdf(Pn2) > Fmm2<-Fm2(1/4) > Fnn2<-Fn2(0) > Fmm2 #0.582 > Fnn2 #0 > > > Pm2<-rbeta(1000, 0.2+1, 0.8+3) #obs5 > Pn2<-rbeta(1000, 0.2+1, 0.8+3) > Fm2<- ecdf(Pm2) > Fn2<- ecdf(Pn2) > Fmm2<-Fm2(1/4) > Fnn2<-Fn2(1/4) > Fmm2 #0.404 > Fnn2 #0.416 > > > > On Sat, Feb 23, 2013 at 10:53 PM, arun kirshna [via R] < > [hidden email] <http://user/SendEmail.jtp?type=node&node=4659769&i=2>> > wrote: > > > Hi, > > d3<-structure(list(m1 = c(2, 3, 2), n1 = c(2, 2, 3), cterm1_P0L = > > c(0.9025, > > 0.857375, 0.9025), cterm1_P1L = c(0.64, 0.512, 0.64), cterm1_P0H = > > c(0.9025, > > 0.9025, 0.857375), cterm1_P1H = c(0.64, 0.64, 0.512)), .Names = c("m1", > > "n1", "cterm1_P0L", "cterm1_P1L", "cterm1_P0H", "cterm1_P1H"), row.names > = > > c(NA, > > 3L), class = "data.frame") > > d2<- data.frame() > > for (m1 in 2:3) { > > for (n1 in 2:3) { > > for (x1 in 0:(m1-1)) { > > for (y1 in 0:(n1-1)) { > > for (m in (m1+2): (7-n1)){ > > for (n in (n1+2):(9-m)){ > > for (x in x1:(x1+m-m1)){ > > for(y in y1:(y1+n-n1)){ > > d2<- rbind(d2,c(m1,n1,x1,y1,m,n,x,y)) > > }}}}}}}} > > colnames(d2)<-c("m1","n1","x1","y1","m","n","x","y") > > #or > > > > res1<-do.call(rbind,lapply(unique(d3$m1),function(m1) > > do.call(rbind,lapply(unique(d3$n1),function(n1) > > do.call(rbind,lapply(0:(m1-1),function(x1) > > do.call(rbind,lapply(0:(n1-1),function(y1) > > do.call(rbind,lapply((m1+2):(7-n1),function(m) > > do.call(rbind,lapply((n1+2):(9-m),function(n) > > do.call(rbind,lapply(x1:(x1+m-m1), function(x) > > do.call(rbind,lapply(y1:(y1+n-n1), function(y) > > expand.grid(m1,n1,x1,y1,m,n,x,y)) ))))))))))))))) > > names(res1)<- c("m1","n1","x1","y1","m","n","x","y") > > attr(res1,"out.attrs")<-NULL > > res1[]<- sapply(res1,as.integer) > > > > library(plyr) > > res2<- join(res1,d3,by=c("m1","n1"),type="inner") > > > > #Assuming that these are the values you used: > > > > p0L<-0.05 > > p0H<-0.05 > > p1L<-0.20 > > p1H<-0.20 > > res2<- within(res2,{p1<- x/m; p2<- y/n;term2_p0<-dbinom(x1,m1, p0L, > > log=FALSE)* dbinom(y1,n1,p0H, log=FALSE)*dbinom(x-x1,m-m1, p0L, > log=FALSE)* > > dbinom(y-y1,n-n1,p0H, log=FALSE);term2_p1<- dbinom(x1,m1, p1L, > log=FALSE)* > > dbinom(y1,n1,p1H, log=FALSE)*dbinom(x-x1,m-m1, p1L, log=FALSE)* > > dbinom(y-y1,n-n1,p1H, log=FALSE);Pm2<-rbeta(240, 0.2+x, > > 0.8+m-x);Pn2<-rbeta(240, 0.2+y, 0.8+n-y)}) > > Fm2<- ecdf(res2$Pm2) > > Fn2<- ecdf(res2$Pn2) > > > > res3<- within(res2,{Fmm2<-Fm2(p1);Fnn2<- Fn2(p2);R2<- (Fmm2+Fnn2)/2}) > #not > > sure about this step especially the Fm2() or Fn2() > > res3$Fmm_f2<-apply(res3[,c("R2","Fmm2")],1,min) > > res3$Fnn_f2<-apply(res3[,c("R2","Fnn2")],1,max) > > res3<- within(res3,{Qm2<- 1-Fmm_f2;Qn2<- 1-Fnn_f2}) > > head(res3) > > # m1 n1 x1 y1 m n x y cterm1_P0L cterm1_P1L cterm1_P0H cterm1_P1H > > Pn2 > > #1 2 2 0 0 4 4 0 0 0.9025 0.64 0.9025 0.64 > > 0.001084648 > > #2 2 2 0 0 4 4 0 1 0.9025 0.64 0.9025 0.64 > > 0.504593909 > > #3 2 2 0 0 4 4 0 2 0.9025 0.64 0.9025 0.64 > > 0.541379357 > > #4 2 2 0 0 4 4 1 0 0.9025 0.64 0.9025 0.64 > > 0.138947785 > > #5 2 2 0 0 4 4 1 1 0.9025 0.64 0.9025 0.64 > > 0.272364957 > > #6 2 2 0 0 4 4 1 2 0.9025 0.64 0.9025 0.64 > > 0.761635059 > > # Pm2 term2_p1 term2_p0 p2 p1 R2 Fnn2 > Fmm2 > > #1 1.212348e-05 0.16777216 0.6634204313 0.00 0.00 0.0000000 0.0000000 > 0.0 > > #2 1.007697e-03 0.08388608 0.0698337296 0.25 0.00 0.1791667 0.3583333 > 0.0 > > #3 1.106946e-05 0.01048576 0.0018377297 0.50 0.00 0.3479167 0.6958333 > 0.0 > > # 2.086758e-01 0.08388608 0.0698337296 0.00 0.25 0.2000000 0.0000000 > 0.4 > > #5 2.382179e-01 0.04194304 0.0073509189 0.25 0.25 0.3791667 0.3583333 > 0.4 > > #6 4.494673e-01 0.00524288 0.0001934452 0.50 0.25 0.5479167 0.6958333 > 0.4 > > # Fmm_f2 Fnn_f2 Qn2 Qm2 > > #1 0.0000000 0.0000000 1.0000000 1.0000000 > > #2 0.0000000 0.3583333 0.6416667 1.0000000 > > #3 0.0000000 0.6958333 0.3041667 1.0000000 > > #4 0.2000000 0.2000000 0.8000000 0.8000000 > > #5 0.3791667 0.3791667 0.6208333 0.6208333 > > #6 0.4000000 0.6958333 0.3041667 0.6000000 > > > > > > A.K. > > > > > > > > > > > > > > > > ________________________________ > > From: Joanna Zhang <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=0>> > > > > To: arun <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=1>> > > > > Sent: Friday, February 22, 2013 11:02 AM > > Subject: Re: [R] cumulative sum by group and under some criteria > > > > > > Thanks! Then I need to create new variables based on the res2. I can't > > find Fmm_f1, Fnn_f2, R2, Qm2, Qn2 until running the code several times > and > > the values of Fnn_f2, Fmm_f2 are correct. > > > > attach(res2) > > res2$p1<-x/m > > res2$p2<-y/n > > res2$term2_p0 <- dbinom(x1,m1, p0L, log=FALSE)* dbinom(y1,n1,p0H, > > log=FALSE)*dbinom(x-x1,m-m1, p0L, log=FALSE)* dbinom(y-y1,n-n1,p0H, > > log=FALSE) > > res2$term2_p1 <- dbinom(x1,m1, p1L, log=FALSE)* dbinom(y1,n1,p1H, > > log=FALSE)*dbinom(x-x1,m-m1, p1L, log=FALSE)* dbinom(y-y1,n-n1,p1H, > > log=FALSE) > > Pm2<-rbeta(1000, 0.2+x, 0.8+m-x) > > Fm2<-ecdf(Pm2) > > res2$Fmm2<-Fm2(x/m) #not correct, it comes out after running code two > > times > > Pn2<-rbeta(1000, 0.2+y, 0.8+n-y) > > Fn2<-ecdf(Pn2) > > res2$Fnn2<-Fn2(y/n) > > res2$R2<-(Fmm2+Fnn2)/2 > > res2$Fmm_f2<-min(R2,Fmm2) # not correct > > res2$Fnn_f2<-max(R2,Fnn2) > > res2$Qm2<-(1-Fmm_f2) > > res2$Qn2<-(1-Fnn_f2) > > detach(res2) > > res2 > > head(res2) > > > > > > > > On Tue, Feb 19, 2013 at 4:09 PM, arun <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=2>> > > wrote: > > > > Hi, > > > > > > > >""suppose that I have a dataset 'd' > > > m1 n1 A B C D > > >1 2 2 0.902500 0.640 0.9025 0.64 > > >2 3 2 0.857375 0.512 0.9025 0.64 > > >I want to add x1 (from 0 to m1), y1(from 0 to n1), m (range from > > >m1+2 to 7-n1), n(from n1+2 to 9-m), x (x1 to x1+m-m1), y(y1 to > y1+n-n1), > > expanding to another dataset 'd2' based on each row (combination of m1 > > >and n1)"" > > > > > > > > >Try: > > > > > > > > > d<-read.table(text=" > > > > > >m1 n1 A B C D > > >1 2 2 0.902500 0.640 0.9025 0.64 > > >2 3 2 0.857375 0.512 0.9025 0.64 > > >",sep="",header=TRUE) > > > > > >vec1<- paste(d[,1],d[,2],d[,3],d[,4],d[,5],d[,6]) > > >res1<- do.call(rbind,lapply(vec1,function(m1) > > do.call(rbind,lapply(0:(as.numeric(substr(m1,1,1))),function(x1) > > do.call(rbind,lapply(0:(as.numeric(substr(m1,3,3))),function(y1) > > > do.call(rbind,lapply((as.numeric(substr(m1,1,1))+2):(7-as.numeric(substr(m1,3,3))),function(m) > > > do.call(rbind,lapply((as.numeric(substr(m1,3,3))+2):(9-m),function(n) > > > > > > do.call(rbind,lapply(x1:(x1+m-as.numeric(substr(m1,1,1))), function(x) > > > do.call(rbind,lapply(y1:(y1+n-as.numeric(substr(m1,3,3))), function(y) > > > expand.grid(m1,x1,y1,m,n,x,y)) ))))))))))))) > > > > > names(res1)<- c("group","x1","y1","m","n","x","y") > > > > > res1$m1<- NA; res1$n1<- NA; res1$A<- NA; res1$B<- NA; res1$C<- > NA;res1$D > > <- NA > > >res1[,8:13]<-do.call(rbind,lapply(strsplit(as.character(res1$group)," > > "),as.numeric)) > > >res2<- res1[,c(8:9,2:7,10:13)] > > > > > > > > > head(res2) > > ># m1 n1 x1 y1 m n x y A B C D > > >#1 2 2 0 0 4 4 0 0 0.9025 0.64 0.9025 0.64 > > >#2 2 2 0 0 4 4 0 1 0.9025 0.64 0.9025 0.64 > > >#3 2 2 0 0 4 4 0 2 0.9025 0.64 0.9025 0.64 > > >#4 2 2 0 0 4 4 1 0 0.9025 0.64 0.9025 0.64 > > >#5 2 2 0 0 4 4 1 1 0.9025 0.64 0.9025 0.64 > > >#6 2 2 0 0 4 4 1 2 0.9025 0.64 0.9025 0.64 > > > > > > > > > > > > > > > > > > > > >________________________________ > > >From: Joanna Zhang <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=3>> > > > > >To: arun <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=4>> > > > > >Sent: Tuesday, February 19, 2013 11:43 AM > > > > > >Subject: Re: [R] cumulative sum by group and under some criteria > > > > > > > > >Thanks. I can get the data I expected (get rid of the m1=3, n1=3) using > > the join and 'inner' code, but just curious about the way to expand the > > data. There should be a way to expand the data based on each row > > (combination of the variables), unique(d3$m1 & d3$n1) ?. > > > > > >or is there a way to use 'data.frame' and 'for' loop to expand directly > > from the data? like res1<-data.frame (d3) for () {.... > > > > > > > > >On Tue, Feb 19, 2013 at 9:55 AM, arun <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=5>> > > wrote: > > > > > >If you can provide me the output that you expect with all the rows of > the > > combination in the res2, I can take a look. > > >> > > >> > > >> > > >> > > >> > > >> > > >>________________________________ > > >> > > >>From: Joanna Zhang <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=6>> > > > > >>To: arun <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=7>> > > > > >> > > >>Sent: Tuesday, February 19, 2013 10:42 AM > > >> > > >>Subject: Re: [R] cumulative sum by group and under some criteria > > >> > > >> > > >>Thanks. But I thougth the expanded dataset 'res1' should not have > > combination of m1=3 and n1=3 because it is based on dataset 'd3' which > > doesn't have m1=3 and n1=3, right?> > > >>>In the example that you provided: > > >>> (m1+2):(maxN-(n1+2)) > > >>>#[1] 5 > > >>> (n1+2):(maxN-5) > > >>>#[1] 4 > > >>>#Suppose > > >>> x1<- 4 > > >>> y1<- 2 > > >>> x1:(x1+5-m1) > > >>>#[1] 4 5 6 > > >>> y1:(y1+4-n1) > > >>>#[1] 2 3 4 > > >>> > > >>> datnew<-expand.grid(5,4,4:6,2:4) > > >>> colnames(datnew)<- c("m","n","x","y") > > >>>datnew<-within(datnew,{p1<- x/m;p2<-y/n}) > > >>>res<-cbind(datnew,d2[rep(1:nrow(d2),nrow(datnew)),]) > > >>> row.names(res)<- 1:nrow(res) > > >>> res > > >>># m n x y p2 p1 m1 n1 cterm1_P1L cterm1_P0H > > >>>#1 5 4 4 2 0.50 0.8 3 2 0.00032 0.0025 > > >>>#2 5 4 5 2 0.50 1.0 3 2 0.00032 0.0025 > > >>>#3 5 4 6 2 0.50 1.2 3 2 0.00032 0.0025 > > >>>#4 5 4 4 3 0.75 0.8 3 2 0.00032 0.0025 > > >>>#5 5 4 5 3 0.75 1.0 3 2 0.00032 0.0025 > > >>>#6 5 4 6 3 0.75 1.2 3 2 0.00032 0.0025 > > >>>#7 5 4 4 4 1.00 0.8 3 2 0.00032 0.0025 > > >>>#8 5 4 5 4 1.00 1.0 3 2 0.00032 0.0025 > > >>>#9 5 4 6 4 1.00 1.2 3 2 0.00032 0.0025 > > >>> > > >>>A.K. > > >>> > > >>> > > >>> > > >>> > > >>> > > >>>----- Original Message ----- > > >>>From: Zjoanna <[hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=8>> > > > > >>>To: [hidden email]< > http://user/SendEmail.jtp?type=node&node=4659514&i=9> > > >>>Cc: > > >>> > > >>>Sent: Sunday, February 10, 2013 6:04 PM > > >>>Subject: Re: [R] cumulative sum by group and under some criteria > > >>> > > >>> > > >>>Hi, > > >>>How to expand or loop for one variable n based on another variable? > for > > >>>example, I want to add m (from m1 to maxN- n1-2) and for each m, I > want > > to > > >>>add n (n1+2 to maxN-m), and similarly add x and y, then I need to do > > some > > >>>calculations. > > >>> > > >>>d3<-data.frame(d2) > > >>> for (m in (m1+2):(maxN-(n1+2)){ > > >>> for (n in (n1+2):(maxN-m)){ > > >>> for (x in x1:(x1+m-m1)){ > > >>> for (y in y1:(y1+n-n1)){ > > >>> p1<- x/m > > >>> p2<- y/n > > >>>}}}} > > >>> > > >>>On Thu, Feb 7, 2013 at 12:16 AM, arun kirshna [via R] < > > >>>[hidden email] < > http://user/SendEmail.jtp?type=node&node=4659514&i=10>> > > wrote: > > >>> > > >>>> Hi, > > >>>> > > >>>> Anyway, just using some random combinations: > > >>>> dnew<- expand.grid(4:10,5:10,6:10,3:7,4:5,6:8) > > >>>> names(dnew)<-c("m","n","x1","y1","x","y") > > >>>> resF<- cbind(dnew,d2[rep(1:nrow(d2),nrow(dnew)),]) > > >>>> > > >>>> row.names(resF)<- 1:nrow(resF) > > >>>> head(resF) > > >>>> # m n x1 y1 x y m1 n1 cterm1_P1L cterm1_P0H > > >>>> #1 4 5 6 3 4 6 3 2 0.00032 0.0025 > > >>>> #2 5 5 6 3 4 6 3 2 0.00032 0.0025 > > >>>> #3 6 5 6 3 4 6 3 2 0.00032 0.0025 > > >>>> #4 7 5 6 3 4 6 3 2 0.00032 0.0025 > > >>>> #5 8 5 6 3 4 6 3 2 0.00032 0.0025 > > >>>> #6 9 5 6 3 4 6 3 2 0.00032 0.0025 > > >>>> > > >>>> nrow(resF) > > >>>> #[1] 6300 > > >>>> I am not sure what you want to do with this. > > >>>> A.K. > > >>>> ________________________________ > > >>>> From: Joanna Zhang <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=0>> > > >>>> > > >>>> To: arun <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=1>> > > >>> > > >>>> > > >>>> Sent: Wednesday, February 6, 2013 10:29 AM > > >>>> Subject: Re: cumulative sum by group and under some criteria > > >>>> > > >>>> > > >>>> Hi, > > >>>> > > >>>> Thanks! I need to do some calculations in the expended data, the > > expended > > >>>> data would be very large, what is an efficient way, doing > > calculations > > >>>> while expending the data, something similiar with the following, or > > >>>> expending data using the code in your message and then add > > calculations in > > >>>> the expended data? > > >>>> > > >>>> d3<-data.frame(d2) > > >>>> for .......{ > > >>>> for { > > >>>> for .... { > > >>>> for .....{ > > >>>> p1<- x/m > > >>>> p2<- y/n > > >>>> .......... > > >>>> }} > > >>>> }} > > >>>> > > >>>> I also modified your code for expending data: > > >>>> dnew<-expand.grid((m1+2):(maxN-(n1+2)),(n1+2):(maxN-m),0:m1,0:n1, > > >>>> x1:(x1+m-m1),y1:(y1+n-n1)) > > >>>> names(dnew)<-c("m","n","x1","y1","x","y") > > >>>> dnew > > >>>> resF<-cbind(dnew[,c(2,1)],d2[rep(1:nrow(d2),nrow(dnew)),]) # > this > > is > > >>>> not correct, how to modify it. > > >>>> resF > > >>>> row.names(resF)<-1:nrow(resF) > > >>>> resF > > >>>> > > >>>> > > >>>> > > >>>> > > >>>> On Tue, Feb 5, 2013 at 2:46 PM, arun <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=2>> > > >>> > > >>>> wrote: > > >>>> > > >>>> Hi, > > >>>> > > >>>> > > > >>>> >You can reduce the steps to reach d2: > > >>>> >res3<- > > >>>> > with(res2,aggregate(cbind(cterm1_P1L,cterm1_P0H),by=list(m1,n1),max)) > > >>>> > > > >>>> >#Change it to: > > >>>> >res3new<- aggregate(.~m1+n1,data=res2[,c(1:2,12:13)],max) > > >>>> >res3new > > >>>> > m1 n1 cterm1_P1L cterm1_P0H > > >>>> >1 2 2 0.01440 0.00273750 > > >>>> >2 3 2 0.00032 0.00250000 > > >>>> >3 2 3 0.01952 0.00048125 > > >>>> >d2<-res3new[res3new[,3]<0.01 & res3new[,4]<0.01,] > > >>>> > > > >>>> > dnew<-expand.grid(4:10,5:10) > > >>>> > names(dnew)<-c("n","m") > > >>>> >resF<-cbind(dnew[,c(2,1)],d2[rep(1:nrow(d2),nrow(dnew)),]) > > >>>> > > > >>>> >row.names(resF)<-1:nrow(resF) > > >>>> > head(resF) > > >>>> ># m n m1 n1 cterm1_P1L cterm1_P0H > > >>>> >#1 5 4 3 2 0.00032 0.0025 > > >>>> >#2 5 5 3 2 0.00032 0.0025 > > >>>> >#3 5 6 3 2 0.00032 0.0025 > > >>>> >#4 5 7 3 2 0.00032 0.0025 > > >>>> >#5 5 8 3 2 0.00032 0.0025 > > >>>> >#6 5 9 3 2 0.00032 0.0025 > > >>>> > > > >>>> >A.K. > > >>>> > > > >>>> >________________________________ > > >>>> >From: Joanna Zhang <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=3>> > > >>>> > > >>>> >To: arun <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=4>> > > >>> > > >>>> > > >>>> >Sent: Tuesday, February 5, 2013 2:48 PM > > >>>> > > > >>>> >Subject: Re: cumulative sum by group and under some criteria > > >>>> > > > >>>> > > > >>>> > Hi , > > >>>> >what I want is : > > >>>> >m n m1 n1 cterm1_P1L cterm1_P0H > > >>>> > 5 4 3 2 0.00032 0.00250000 > > >>>> > 5 5 3 2 0.00032 0.00250000 > > >>>> > 5 6 3 2 0.00032 0.00250000 > > >>>> > 5 7 3 2 0.00032 0.00250000 > > >>>> > 5 8 3 2 0.00032 0.00250000 > > >>>> > 5 9 3 2 0.00032 0.00250000 > > >>>> >5 10 3 2 0.00032 0.00250000 > > >>>> >6 4 3 2 0.00032 0.00250000 > > >>>> >6 5 3 2 0.00032 0.00250000 > > >>>> >6 6 3 2 0.00032 0.00250000 > > >>>> >6 7 3 2 0.00032 0.00250000 > > >>>> >..... > > >>>> >6 10 3 2 0.00032 0.00250000 > > >>>> > > > >>>> > > > >>>> > > > >>>> >On Tue, Feb 5, 2013 at 1:12 PM, arun <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=5>> > > >>> > > >>>> wrote: > > >>>> > > > >>>> >Hi, > > >>>> >> > > >>>> >>Saw your message on Nabble. > > >>>> >> > > >>>> >> > > >>>> >>"I want to add some more columns based on the results. Is the > > following > > >>>> code good way to create such a data frame and How to see the column > m > > and n > > >>>> in the updated data? > > >>>> >> > > >>>> >>d2<- reres3[res3[,3]<0.01 & res3[,4]<0.01,] > > >>>> >># should be a typo > > >>>> >> > > >>>> >>colnames(d2)[1:2]<- c("m1","n1"); > > >>>> >>d2 #already a data.frame > > >>>> >> > > >>>> >>d3<-data.frame(d2) > > >>>> >> for (m in (m1+2):10){ > > >>>> >> for (n in (n1+2):10){ > > >>>> >> d3<-rbind(d3, c(d2))}}" #this is not making much sense to me. > > >>>> Especially, you mentioned you wanted add more columns. > > >>>> >>#Running this step gave error > > >>>> >>#Error: object 'm1' not found > > >>>> >> > > >>>> >>Not sure what you want as output. > > >>>> >>Could you show the ouput that is expected: > > >>>> >> > > >>>> >>A.K. > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >>________________________________ > > >>>> >>From: Joanna Zhang <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=6>> > > >>>> > > >>>> >>To: arun <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=7>> > > >>> > > >>>> > > >>>> >>Sent: Tuesday, February 5, 2013 10:23 AM > > >>>> >> > > >>>> >>Subject: Re: cumulative sum by group and under some criteria > > >>>> >> > > >>>> >> > > >>>> >>Hi, > > >>>> >> > > >>>> >>Yes, I changed code. You answered the questions. But how can I > put > > two > > >>>> criteria in the code, if both the maximum value of cterm1_p1L <= > 0.01 > > and > > >>>> cterm1_p1H <=0.01, the output the m1,n1. > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >> > > >>>> >>On Tue, Feb 5, 2013 at 8:47 AM, arun <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=8>> > > >>> > > >>>> wrote: > > >>>> >> > > >>>> >> > > >>>> >>> > > >>>> >>> HI, > > >>>> >>> > > >>>> >>> > > >>>> >>>I am not getting the same results as yours: You must have > changed > > the > > >>>> dataset. > > >>>> >>> res2[,1:2][res2$cterm1_P1L<0.6 & res2$cterm1_P0H<0.95,] > > >>>> >>> m1 n1 > > >>>> >>>1 2 2 > > >>>> >>>2 2 2 > > >>>> >>>3 2 2 > > >>>> >>>4 2 2 > > >>>> >>>5 2 2 > > >>>> >>>6 2 2 > > >>>> >>>7 2 2 > > >>>> >>>8 2 2 > > >>>> >>>9 2 2 > > >>>> >>>10 3 2 > > >>>> >>>11 3 2 > > >>>> >>>12 3 2 > > >>>> >>>13 3 2 > > >>>> >>>14 3 2 > > >>>> >>>15 3 2 > > >>>> >>>16 3 2 > > >>>> >>>17 3 2 > > >>>> >>>18 3 2 > > >>>> >>>19 3 2 > > >>>> >>>20 3 2 > > >>>> >>>21 3 2 > > >>>> >>>22 2 3 > > >>>> >>>23 2 3 > > >>>> >>>24 2 3 > > >>>> >>>25 2 3 > > >>>> >>>26 2 3 > > >>>> >>>27 2 3 > > >>>> >>>28 2 3 > > >>>> >>>29 2 3 > > >>>> >>>30 2 3 > > >>>> >>>31 2 3 > > >>>> >>>32 2 3 > > >>>> >>>33 2 3 > > >>>> >>> > > >>>> >>> > > >>>> >>>Regarding the maximum value within each block, haven't I > answered > > in > > >>>> the earlier post. > > >>>> >>> > > >>>> >>>aggregate(cterm1_P1L~m1+n1,data=res2,max) > > >>>> >>># m1 n1 cterm1_P1L > > >>>> >>>#1 2 2 0.01440 > > >>>> >>>#2 3 2 0.00032 > > >>>> >>>#3 2 3 0.01952 > > >>>> >>> > > >>>> >>> > > >>>> >>> > > with(res2,aggregate(cbind(cterm1_P1L,cterm1_P0H),by=list(m1,n1),max)) > > >>>> >>># Group.1 Group.2 cterm1_P1L cterm1_P0H > > >>>> >>>#1 2 2 0.01440 0.00273750 > > >>>> >>>#2 3 2 0.00032 0.00250000 > > >>>> >>>#3 2 3 0.01952 0.00048125 > > >>>> >>> > > >>>> >>> > > >>>> >>>A.K. > > >>>> >>> > > >>>> >>> > > >>>> >>>----- Original Message ----- > > >>> > > >>>> >>>From: "[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=9>";;;; > > >>>> <[hidden email] < > > http://user/SendEmail.jtp?type=node&node=4657773&i=10>> > > >>>> >>>To: [hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=11> > > >>>> >>>Cc: > > >>>> >>> > > >>>> >>>Sent: Tuesday, February 5, 2013 9:33 AM > > >>>> >>>Subject: Re: cumulative sum by group and under some criteria > > >>>> >>> > > >>>> >>>Hi, > > >>>> >>>If use this > > >>>> >>> > > >>>> >>>res2[,1:2][res2$cterm1_P1L<0.6 & res2$cterm1_P0H<0.95,] > > >>>> >>> > > >>>> >>>the results are the following, but actually only m1=3, n1=2 > > sastify the > > >>>> criteria, as I need to look at the row with maximum value within > each > > >>>> block,not every row. > > >>>> >>> > > >>>> >>> > > >>>> >>> m1 n1 > > >>>> >>>1 2 2 > > >>>> >>>10 3 2 > > >>>> >>>11 3 2 > > >>>> >>>12 3 2 > > >>>> >>>13 3 2 > > >>>> >>>14 3 2 > > >>>> >>>15 3 2 > > >>>> >>>16 3 2 > > >>>> >>>17 3 2 > > >>>> >>>18 3 2 > > >>>> >>>19 3 2 > > >>>> >>>20 3 2 > > >>>> >>>21 3 2 > > >>>> >>>22 2 3 > > >>>> >>>23 2 3 > > >>>> >>> > > >>>> >>> > > >>>> >>><quote author='arun kirshna'> > > >>>> >>> > > >>>> >>> > > >>>> >>> > > >>>> >>>Hi, > > >>>> >>>Thanks. This extract every row that satisfy the condition, but I > > need > > >>>> look > > >>>> >>>at the last row (the maximum of cumulative sum) for each block > > (m1,n1). > > >>>> for > > >>>> >>>example, if I set the criteria > > >>>> >>> > > >>>> >>>res2$cterm1_P1L<0.6 & res2$cterm1_P0H<0.95, this should extract > > m1= 3, > > >>>> n1 = > > >>>> >>>2. > > >>>> >>> > > >>>> >>> > > >>>> >>>Hi, > > >>>> >>>I am not sure I understand your question. > > >>>> >>>res2$cterm1_P1L<0.6 & res2$cterm1_P0H<0.95 > > >>>> >>> #[1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE > TRUE > > TRUE > > >>>> TRUE > > >>>> >>>TRUE > > >>>> >>>#[16] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE > TRUE > > TRUE > > >>>> TRUE > > >>>> >>>TRUE > > >>>> >>>#[31] TRUE TRUE TRUE > > >>>> >>> > > >>>> >>>This will extract all the rows. > > >>>> >>> > > >>>> >>> > > >>>> >>>res2[,1:2][res2$cterm1_P1L<0.01 & res2$cterm1_P1L!=0,] > > >>>> >>># m1 n1 > > >>>> >>>#21 3 2 > > >>>> >>>This extract only the row you wanted. > > >>>> >>> > > >>>> >>>For the different groups: > > >>>> >>> > > >>>> >>>aggregate(cterm1_P1L~m1+n1,data=res2,max) > > >>>> >>># m1 n1 cterm1_P1L > > >>>> >>>#1 2 2 0.01440 > > >>>> >>>#2 3 2 0.00032 > > >>>> >>>#3 2 3 0.01952 > > >>>> >>> > > >>>> >>> aggregate(cterm1_P1L~m1+n1,data=res2,function(x) max(x)<0.01) > > >>>> >>> # m1 n1 cterm1_P1L > > >>>> >>>#1 2 2 FALSE > > >>>> >>>#2 3 2 TRUE > > >>>> >>>#3 2 3 FALSE > > >>>> >>> > > >>>> >>>res4<-aggregate(cterm1_P1L~m1+n1,data=res2,function(x) > > max(x)<0.01) > > >>>> >>>res4[,1:2][res4[,3],] > > >>>> >>># m1 n1 > > >>>> >>>#2 3 2 > > >>>> >>> > > >>>> >>>A.K. > > >>>> >>> > > >>>> >>> > > >>>> >>> > > >>>> >>> > > >>>> >>>----- Original Message ----- > > >>> > > >>>> >>>From: "[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=12>";;;; > > >>>> <[hidden email] < > > http://user/SendEmail.jtp?type=node&node=4657773&i=13>> > > >>>> >>>To: [hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=14> > > >>>> >>>Cc: > > >>>> >>>Sent: Sunday, February 3, 2013 3:58 PM > > >>>> >>>Subject: Re: cumulative sum by group and under some criteria > > >>>> >>> > > >>>> >>>Hi, > > >>>> >>>Let me restate my questions. I need to get the m1 and n1 that > > satisfy > > >>>> some > > >>>> >>>criteria, for example in this case, within each group, the > maximum > > >>>> >>>cterm1_p1L ( the last row in this group) <0.01. I need to > extract > > m1=3, > > >>>> >>>n1=2, I only need m1, n1 in the row. > > >>>> >>> > > >>>> >>>Also, how to create the structure from the data.frame, I am new > to > > R, I > > >>>> need > > >>>> >>>to change the maxN and run the loop to different data. > > >>>> >>>Thanks very much for your help! > > >>>> >>> > > >>>> >>><quote author='arun kirshna'> > > >>>> >>>HI, > > >>>> >>> > > >>>> >>>I think this should be more correct: > > >>>> >>>maxN<-9 > > >>>> >>>c11<-0.2 > > >>>> >>>c12<-0.2 > > >>>> >>>p0L<-0.05 > > >>>> >>>p0H<-0.05 > > >>>> >>>p1L<-0.20 > > >>>> >>>p1H<-0.20 > > >>>> >>> > > >>>> >>>d <- structure(list(m1 = c(2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, > 2, > > >>>> >>>2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3), > > >>>> >>> n1 = c(2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, > > >>>> >>> 3, 3, 3, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2), x1 = c(0, > > >>>> >>> 0, 0, 1, 1, 1, 2, 2, 2, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, > > >>>> >>> 2, 0, 0, 0, 1, 1, 1, 2, 2, 2, 3, 3, 3), y1 = c(0, 1, 2, 0, > > >>>> >>> 1, 2, 0, 1, 2, 0, 1, 2, 3, 0, 1, 2, 3, 0, 1, 2, 3, 0, 1, > > >>>> >>> 2, 0, 1, 2, 0, 1, 2, 0, 1, 2), Fmm = c(0, 0, 0, 0.7, 0.59, > > >>>> >>> 0.64, 1, 1, 1, 0, 0, 0, 0, 0.63, 0.7, 0.74, 0.68, 1, 1, 1, > > >>>> >>> 1, 0, 0, 0, 0.62, 0.63, 0.6, 0.63, 0.6, 0.68, 1, 1, 1), Fnn > = > > c(0, > > >>>> >>> 0.64, 1, 0, 0.51, 1, 0, 0.67, 1, 0, 0.62, 0.69, 1, 0, 0.54, > > >>>> >>> 0.62, 1, 0, 0.63, 0.73, 1, 0, 0.63, 1, 0, 0.7, 1, 0, 0.7, > > >>>> >>> 1, 0, 0.58, 1), Qm = c(1, 1, 1, 0.65, 0.45, 0.36, 0.5, > 0.165, > > >>>> >>> 0, 1, 1, 1, 1, 0.685, 0.38, 0.32, 0.32, 0.5, 0.185, 0.135, > > >>>> >>> 0, 1, 1, 1, 0.69, 0.37, 0.4, 0.685, 0.4, 0.32, 0.5, 0.21, > > >>>> >>> 0), Qn = c(1, 0.36, 0, 0.65, 0.45, 0, 0.5, 0.165, 0, 1, > 0.38, > > >>>> >>> 0.31, 0, 0.685, 0.38, 0.32, 0, 0.5, 0.185, 0.135, 0, 1, > 0.37, > > >>>> >>> 0, 0.69, 0.3, 0, 0.685, 0.3, 0, 0.5, 0.21, 0), term1_p0 = > > >>>> c(0.81450625, > > >>>> >>> 0.0857375, 0.00225625, 0.0857375, 0.009025, 0.0002375, > > 0.00225625, > > >>>> >>> 0.0002375, 6.25e-06, 0.7737809375, 0.1221759375, > > >>>> 0.00643031249999999, > > >>>> >>> 0.0001128125, 0.081450625, 0.012860625, 0.000676875, > > 1.1875e-05, > > >>>> >>> 0.0021434375, 0.0003384375, 1.78125e-05, 3.125e-07, > > 0.7737809375, > > >>>> >>> 0.081450625, 0.0021434375, 0.1221759375, 0.012860625, > > >>>> 0.0003384375, > > >>>> >>> 0.00643031249999999, 0.000676875, 1.78125e-05, 0.0001128125, > > >>>> >>> 1.1875e-05, 3.125e-07), term1_p1 = c(0.4096, 0.2048, 0.0256, > > >>>> >>> 0.2048, 0.1024, 0.0128, 0.0256, 0.0128, 0.0016, 0.32768, > > >>>> >>> 0.24576, 0.06144, 0.00512, 0.16384, 0.12288, 0.03072, > 0.00256, > > >>>> >>> 0.02048, 0.01536, 0.00384, 0.00032, 0.32768, 0.16384, > 0.02048, > > >>>> >>> 0.24576, 0.12288, 0.01536, 0.06144, 0.03072, 0.00384, > 0.00512, > > >>>> >>> 0.00256, 0.00032)), .Names = c("m1", "n1", "x1", "y1", > "Fmm", > > >>>> >>>"Fnn", "Qm", "Qn", "term1_p0", "term1_p1"), row.names = c(NA, > > >>>> >>>33L), class = "data.frame") > > >>>> >>> > > >>>> >>>library(zoo) > > >>>> >>>lst1<- split(d,list(d$m1,d$n1)) > > >>>> > >>>res2<-do.call(rbind,lapply(lst1[lapply(lst1,nrow)!=0],function(x){ > > >>>> >>>x[,11:14]<-NA; > > >>>> >>>x[,11:12][x$Qm<=c11,]<-cumsum(x[,9:10][x$Qm<=c11,]); > > >>>> >>>x[,13:14][x$Qn<=c12,]<-cumsum(x[,9:10][x$Qn<=c12,]); > > >>>> >>>colnames(x)[11:14]<- > > >>>> c("cterm1_P0L","cterm1_P1L","cterm1_P0H","cterm1_P1H"); > > >>>> >>>x1<-na.locf(x); > > >>>> >>>x1[,11:14][is.na(x1[,11:14])]<-0; > > >>>> >>>x1})) > > >>>> >>>row.names(res2)<- 1:nrow(res2) > > >>>> >>> > > >>>> >>> res2 > > >>>> >>> # m1 n1 x1 y1 Fmm Fnn Qm Qn term1_p0 term1_p1 > > >>>> cterm1_P0L > > >>>> >>>cterm1_P1L cterm1_P0H cterm1_P1H > > >>>> >>> > > >>>> >>>#1 2 2 0 0 0.00 0.00 1.000 1.000 0.8145062500 0.40960 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#2 2 2 0 1 0.00 0.64 1.000 0.360 0.0857375000 0.20480 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#3 2 2 0 2 0.00 1.00 1.000 0.000 0.0022562500 0.02560 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0022562500 0.02560 > > >>>> >>>#4 2 2 1 0 0.70 0.00 0.650 0.650 0.0857375000 0.20480 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0022562500 0.02560 > > >>>> >>>#5 2 2 1 1 0.59 0.51 0.450 0.450 0.0090250000 0.10240 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0022562500 0.02560 > > >>>> >>>#6 2 2 1 2 0.64 1.00 0.360 0.000 0.0002375000 0.01280 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024937500 0.03840 > > >>>> >>>#7 2 2 2 0 1.00 0.00 0.500 0.500 0.0022562500 0.02560 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024937500 0.03840 > > >>>> >>>#8 2 2 2 1 1.00 0.67 0.165 0.165 0.0002375000 0.01280 > > >>>> 0.0002375000 > > >>>> >>> 0.01280 0.0027312500 0.05120 > > >>>> >>>#9 2 2 2 2 1.00 1.00 0.000 0.000 0.0000062500 0.00160 > > >>>> 0.0002437500 > > >>>> >>> 0.01440 0.0027375000 0.05280 > > >>>> >>>#10 3 2 0 0 0.00 0.00 1.000 1.000 0.7737809375 0.32768 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#11 3 2 0 1 0.00 0.63 1.000 0.370 0.0814506250 0.16384 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#12 3 2 0 2 0.00 1.00 1.000 0.000 0.0021434375 0.02048 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0021434375 0.02048 > > >>>> >>>#13 3 2 1 0 0.62 0.00 0.690 0.690 0.1221759375 0.24576 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0021434375 0.02048 > > >>>> >>>#14 3 2 1 1 0.63 0.70 0.370 0.300 0.0128606250 0.12288 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0021434375 0.02048 > > >>>> >>>#15 3 2 1 2 0.60 1.00 0.400 0.000 0.0003384375 0.01536 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024818750 0.03584 > > >>>> >>>#16 3 2 2 0 0.63 0.00 0.685 0.685 0.0064303125 0.06144 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024818750 0.03584 > > >>>> >>>#17 3 2 2 1 0.60 0.70 0.400 0.300 0.0006768750 0.03072 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024818750 0.03584 > > >>>> >>>#18 3 2 2 2 0.68 1.00 0.320 0.000 0.0000178125 0.00384 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024996875 0.03968 > > >>>> >>>#19 3 2 3 0 1.00 0.00 0.500 0.500 0.0001128125 0.00512 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024996875 0.03968 > > >>>> >>>#20 3 2 3 1 1.00 0.58 0.210 0.210 0.0000118750 0.00256 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0024996875 0.03968 > > >>>> >>>#21 3 2 3 2 1.00 1.00 0.000 0.000 0.0000003125 0.00032 > > >>>> 0.0000003125 > > >>>> >>> 0.00032 0.0025000000 0.04000 > > >>>> >>>#22 2 3 0 0 0.00 0.00 1.000 1.000 0.7737809375 0.32768 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#23 2 3 0 1 0.00 0.62 1.000 0.380 0.1221759375 0.24576 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#24 2 3 0 2 0.00 0.69 1.000 0.310 0.0064303125 0.06144 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0000000000 0.00000 > > >>>> >>>#25 2 3 0 3 0.00 1.00 1.000 0.000 0.0001128125 0.00512 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0001128125 0.00512 > > >>>> >>>#26 2 3 1 0 0.63 0.00 0.685 0.685 0.0814506250 0.16384 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0001128125 0.00512 > > >>>> >>>#27 2 3 1 1 0.70 0.54 0.380 0.380 0.0128606250 0.12288 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0001128125 0.00512 > > >>>> >>>#28 2 3 1 2 0.74 0.62 0.320 0.320 0.0006768750 0.03072 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0001128125 0.00512 > > >>>> >>>#29 2 3 1 3 0.68 1.00 0.320 0.000 0.0000118750 0.00256 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0001246875 0.00768 > > >>>> >>>#30 2 3 2 0 1.00 0.00 0.500 0.500 0.0021434375 0.02048 > > >>>> 0.0000000000 > > >>>> >>> 0.00000 0.0001246875 0.00768 > > >>>> >>>#31 2 3 2 1 1.00 0.63 0.185 0.185 0.0003384375 0.01536 > > >>>> 0.0003384375 > > >>>> >>> 0.01536 0.0004631250 0.02304 > > >>>> >>>#32 2 3 2 2 1.00 0.73 0.135 0.135 0.0000178125 0.00384 > > >>>> 0.0003562500 > > >>>> >>> 0.01920 0.0004809375 0.02688 > > >>>> >>>#33 2 3 2 3 1.00 1.00 0.000 0.000 0.0000003125 0.00032 > > >>>> 0.0003565625 > > >>>> >>> 0.01952 0.0004812500 0.02720 > > >>>> >>> > > >>>> >>>#Sorry, some values in my previous solution didn't look right. I > > >>>> didn't > > >>>> >>>A.K. > > >>>> >>> > > >>>> >>> > > >>>> >>> > > >>>> >>> > > >>>> >>> > > >>>> >>>----- Original Message ----- > > >>>> >>>From: Zjoanna <[hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=15>> > > >>>> > > >>>> >>>To: [hidden email]< > > http://user/SendEmail.jtp?type=node&node=4657773&i=16> > > >>> > > >>>> >>>Cc: > > >>>> >>>Sent: Friday, February 1, 2013 12:19 PM > > >>>> >>>Subject: Re: [R] cumulative sum by group and under some criteria > > >>>> >>> > > >>>> >>>Thank you very much for your reply. Your code work well with > this > > >>>> example. > > >>>> >>>I modified a little to fit my real data, I got an error massage. > > >>>> >>> > > >>>> >>>Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, > > ...) : > > >>>> >>> Group length is 0 but data length > 0 > > >>>> >>> > > >>>> >>> > > >>>> >>>On Thu, Jan 31, 2013 at 12:21 PM, arun kirshna [via R] < > > >>>> >>>[hidden email] < > > http://user/SendEmail.jtp?type=node&node=4657773&i=17>> > > >>> > > >>>> wrote: > > >>>> >>> > > >>>> >>>> Hi, > > >>>> >>>> Try this: > > >>>> >>>> colnames(d)<-c("m1","n1","x1","y1","p11","p12") > > >>>> >>>> library(zoo) > > >>>> >>>> res1<- > > >>>> do.call(rbind,lapply(lapply(split(d,list(d$m1,d$n1)),function(x) > > >>>> >>>> {x$cp11[x$x1>1]<- cumsum(x$p11[x$x1>1]);x$cp12[x$y1>1]<- > > >>>> >>>> cumsum(x$p12[x$y1>1]);x}),function(x) > > >>>> >>>> {x$cp11<-na.locf(x$cp11,na.rm=F);x$cp12<- > > >>>> na.locf(x$cp12,na.rm=F);x})) > > >>>> >>>> #there would be a warning here as one of the list element is > > NULL. > > >>>> The, > > >>>> >>>> warning is okay > > >>>> >>>> row.names(res1)<- 1:nrow(res1) > > >>>> >>>> res1[,7:8][is.na(res1[,7:8])]<- 0 > > >>>> >>>> res1 > > >>>> >>>> # m1 n1 x1 y1 p11 p12 cp11 cp12 > > >>>> >>>> #1 2 2 0 0 0.00 0.00 0.00 0.00 > > >>>> >>>> #2 2 2 0 1 0.00 0.50 0.00 0.00 > > >>>> >>>> #3 2 2 0 2 0.00 1.00 0.00 1.00 > > >>>> >>>> #4 2 2 1 0 0.50 0.00 0.00 1.00 > > >>>> >>>> #5 2 2 1 1 0.50 0.50 0.00 1.00 > > >>>> >>>> #6 2 2 1 2 0.50 1.00 0.00 2.00 > > >>>> >>>> #7 2 2 2 0 1.00 0.00 1.00 2.00 > > >>>> >>>> #8 2 2 2 1 1.00 0.50 2.00 2.00 > > >>>> >>>> #9 2 2 2 2 1.00 1.00 3.00 3.00 > > >>>> >>>> #10 3 2 0 0 0.00 0.00 0.00 0.00 > > >>>> >>>> #11 3 2 0 1 0.00 0.50 0.00 0.00 > > >>>> >>>> #12 3 2 0 2 0.00 1.00 0.00 1.00 > > >>>> >>>> #13 3 2 1 0 0.33 0.00 0.00 1.00 > > >>>> >>>> #14 3 2 1 1 0.33 0.50 0.00 1.00 > > >>>> >>>> #15 3 2 1 2 0.33 1.00 0.00 2.00 > > >>>> >>>> #16 3 2 2 0 0.67 0.00 0.67 2.00 > > >>>> >>>> #17 3 2 2 1 0.67 0.50 1.34 2.00 > > >>>> >>>> #18 3 2 2 2 0.67 1.00 2.01 3.00 > > >>>> >>>> #19 3 2 3 0 1.00 0.00 3.01 3.00 > > >>>> >>>> #20 3 2 3 1 1.00 0.50 4.01 3.00 > > >>>> >>>> #21 3 2 3 2 1.00 1.00 5.01 4.00 > > >>>> >>>> #22 2 3 0 0 0.00 0.00 0.00 0.00 > > >>>> >>>> #23 2 3 0 1 0.00 0.33 0.00 0.00 > > >>>> >>>> #24 2 3 0 2 0.00 0.67 0.00 0.67 > > >>>> >>>> #25 2 3 0 3 0.00 1.00 0.00 1.67 > > >>>> >>>> #26 2 3 1 0 0.50 0.00 0.00 1.67 > > >>>> >>>> #27 2 3 1 1 0.50 0.33 0.00 1.67 > > >>>> >>>> #28 2 3 1 2 0.50 0.67 0.00 2.34 > > >>>> >>>> #29 2 3 1 3 0.50 1.00 0.00 3.34 > > >>>> >>>> #30 2 3 2 0 1.00 0.00 1.00 3.34 > > >>>> >>>> #31 2 3 2 1 1.00 0.33 2.00 3.34 > > >>>> >>>> #32 2 3 2 2 1.00 0.67 3.00 4.01 > > >>>> >>>> #33 2 3 2 3 1.00 1.00 4.00 5.01 > > >>>> >>>> A.K. > > >>>> >>>> > > >>>> >>>> ------------------------------ > > >>>> >>>> If you reply to this email, your message will be added to the > > >>>> discussion > > >>>> >>>> below: > > >>>> >>>> > > >>>> >>>> > > >>>> > > > 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[[alternative HTML version deleted]] > > >>>> >>> > > >>>> >>>______________________________________________ > > >>>> >>>[hidden email] < > > http://user/SendEmail.jtp?type=node&node=4657773&i=18>mailing list > > >>> > > >>>> >>>https://stat.ethz.ch/mailman/listinfo/r-help > > >>>> >>>PLEASE do read the posting guide > > >>>> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html> > <http://www.r-project.org/posting-guide.html> > > <http://www.r-project.org/posting-guide.html> > > >>> > > >>>> >>>and provide commented, minimal, self-contained, reproducible > code. > > >>>> >>> > > >>>> >>> > > >>>> >>>______________________________________________ > > >>>> >>>[hidden email] < > > http://user/SendEmail.jtp?type=node&node=4657773&i=19>mailing list > > >>> > > >>>> >>>https://stat.ethz.ch/mailman/listinfo/r-help > > >>>> >>>PLEASE do read the posting guide > > >>>> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html> > 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[[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
