Learned a new trick. thanks!
Zech
On Fri, Mar 8, 2013 at 6:41 PM, William Dunlap <wdun...@tibco.com> wrote:
> Try using the combination
> plot.new() ; par(new=TRUE)
> to advance to the next position in the layout before querying par("pin").
> Be sure to actually plot something after the par(new=TRUE).
>
> E.g.,
> > layout(matrix(c(1,2,3,4), nrow=2), width=c(1,3), height=c(1,3))
> > plot.new() ; par(new=TRUE)
> > par("pin")
> [1] 0.6624667 0.1623834
> > plot(10:19, main="One")
> > par("pin")
> [1] 0.6624667 0.1623834
> >
> > plot.new() ; par(new=TRUE)
> > par("pin")
> [1] 0.6624667 3.5415500
> > plot(20:29, main="Two")
> > par("pin")
> [1] 0.6624667 3.5415500
>
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
> > -----Original Message-----
> > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf
> > Of Not To Miss
> > Sent: Friday, March 08, 2013 5:12 PM
> > To: r-help
> > Subject: [R] get current plot dimensions?
> >
> > Hi R users,
> >
> > I find par("pin") is kind of confusing (or maybe just me?). The manual
> said
> > it will give " The current plot dimensions, '(width,height)', in inches."
> > The word "current" is the key here. I thought it would give the
> dimensions
> > of the to-be plot, but it actually gives the dimension of the finished
> plot:
> >
> > > layout(matrix(c(1,2,3,4), nrow=2), width=c(1,3), height=c(1,3))
> > > par("pin")
> > [1] 4.216666 3.721324
> > > plot(x)
> > > par("pin")
> > [1] 0.7194221 0.2223079
> > > plot(x)
> > > par("pin")
> > [1] 0.7194221 3.7213237
> > > plot(x)
> > > par("pin")
> > [1] 4.2166662 0.2223079
> > > plot(x)
> >
> >
> > So, if par("pin") doesn't give to-be plot, how can I get its dimension?
> >
> > Thanks,
> > Zech
> >
> > [[alternative HTML version deleted]]
>
>
[[alternative HTML version deleted]]
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