Hi Andras,
what about:
> d[-(1:length(f)), ]
a b
[1,] 3 8
[2,] 4 9
[3,] 5 10
Best,
Gergely
On 20 March 2013 22:53, Andras Farkas <motyoc...@yahoo.com> wrote:
> Dear All,
>
> sorry, got stuck again on the following: let us say we have:
>
> a <-c(1:5)
> b <-c(6:10)
> d <-cbind(a,b)
>
>
> from d I would like to remove total number of rows based on the length of
> f. So if:
>
> f <-c(1)
>
> my result is working great with the following solution:
>
> d[-length(f),]
>
> so I get: a b
> [1,] 2 7
> [2,] 3 8
> [3,] 4 9
> [4,] 5 10 but if I do: f <-c(1,2) then I get: a b
> [1,] 1 6
> [2,] 3 8
> [3,] 4 9
> [4,] 5 10 which tells us ideed, the code works well:-), but it is not what
> I need Instead, I wanted to remove row #1 adn row#2 from the matrix to
> get: [1,] 3 8
> [2,] 4 9
> [3,] 5 10 as the end result. Please provide your insights to solve this
> problem. Any input would be greatly appreciated, thanks, Andras
> [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
