I have fixed it like that:
keep<-matrix(data=rnorm(900,80,20),nrow=30,ncol=30) ShrinkTo<-500 idx<-cut(1:nrow(keep), ShrinkTo) keep.ag<-aggregate(keep, list(idx), mean) PlotMe<-data.matrix(keep.ag[2:ShrinkTo]) The only problem is that takes ages to finish..... Would it be possible to convert it to something like lapply? Regards Alex ________________________________ From: PIKAL Petr <petr.pi...@precheza.cz> Sent: Wednesday, March 27, 2013 4:02 PM Subject: RE: [R] Averaging Out many rows from a column AND funtion to string Hi  > str(as.matrix(keep.ag[,-1]) )  # does look like numeric num [1:10, 1:30] 75.1 93 79 81.7 76.3 ... - attr(*, "dimnames")=List of 2  ..$ : NULL  ..$ : chr [1:30] "V1" "V2" "V3" "V4" ...  Please read and follow what was recommended.  quote  use as.matrix(data.frame) on numeric part                                                          ^^^^^^^^^^^  aggregate produces data frame with its first column being your idx variable, which is factor. Trying to convert it whole to matrix results in character matrix. You need to exclude first column from conversion  And please can you explain how mean(rnorm(whatever)) shall be integer?  Regards Petr  Sent: Wednesday, March 27, 2013 3:01 PM To: PIKAL Petr; R help Subject: Re: [R] Averaging Out many rows from a column AND funtion to string  see inline   ________________________________ From:PIKAL Petr <petr.pi...@precheza.cz> Sent: Wednesday, March 27, 2013 1:50 PM Subject: RE: [R] Averaging Out many rows from a column AND funtion to string Hi  Sent: Wednesday, March 27, 2013 11:46 AM To: PIKAL Petr; R help Subject: Re: [R] Averaging Out many rows from a column AND funtion to string  see inline  ________________________________ From:PIKAL Petr <petr.pi...@precheza.cz> Sent: Wednesday, March 27, 2013 11:24 AM Subject: RE: [R] Averaging Out many rows from a column AND funtion to string Hi > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- > project.org] On Behalf Of Alaios > Sent: Wednesday, March 27, 2013 9:13 AM > To: R help > Subject: [R] Averaging Out many rows from a column AND funtion to > string > > Dear all, > 1) I have a very large matrix of > str(keep) >  num [1:153899, 1:3415] -98.6 -95.8 -96.4 -95.8 -98 ... > that I would like to reduce its size to something like > > str(keep) >  num [1:1000, 1:3415] -98.6 -95.8 -96.4 -95.8 -98 ... or anything > similar in size as this is a matrix that needs plotting (so is ok if it > is 1000 row, 995, or 1123) > > I think what I need here is a way of selecting multiple rows and > averaging per column (notice that the column number should stay the > same) Make an index variable and aggregate values according it Something like idx<-cut(1:153899, 153) keep.ag<-aggregate(keep, list(idx), mean) 1) Thanks that returned a data frame.. How I can have a matrix at the end? use as.matrix(data.frame) on numeric part  a bit of my code that you can re run. I convert a 30,30 matrix to a 10,30. but it looks at the end that I do not get the Data part of the data.fram correctly: Data<-matrix(data=rnorm(900,80,20),nrow=30,ncol=30) idx<-cut(1:30, 10) keep.ag<-aggregate(Data, list(idx), mean) str(as.matrix(keep.ag) ) # it does not look like integers        2) I want to have a string that can be used also for calling a function with the same name. Think of using "mean" to call mean. I need to have R interpret the string in different ways. To call âmeanâ of what? I am sure I do not understand what is your intention. LogFunction<- function(){} FunctionIndex<- rbind (c(1,"LogFunction"),               c(2,"TakeFunction")) print(sprintf('Using the function %s',FunctionIndex[1,1])) This does not contain much clue. Regards Petr PS. Do not use HTML mail messages. Regards Alex > > b. I would like to be able to convert strings that are function names > to real function calls. For example I have something like > > LogFunction<- function(){} > FunctionIndex<- rbind (c(1,"LogFunction"), >             c(2,"TakeFunction") >            ) > print(sprintf('Using the function %s',FunctionIndex[1,1])) # call the > FunctionIndex[1,1] somehow I am not sure if I understand correctly. Is this what you want? myf <-function(fun="mean", arg) eval(call(fun, arg)) Regards Petr > > > > I would like to thank you in advance for your help > > Regards > Alex > >    [[alternative HTML version deleted]] [[alternative HTML version deleted]]
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