On May 29, 2013, at 17:23 , Stefano Sofia wrote: > > Dear R-users, > in case of linear model, > lm(Y ~ X) > is equivalent to > glm(Y ~ X, family=gaussian(link=identity)) > > In case of the exponential model > lm(log(Y) ~ X) > why > glm(Y ~ X, family=gaussian(link=log)) > is not equivalent?
Y is assumed lognormal in one case, normal in the other. > Is there an equivalent glm to lm(log(Y) ~ X)? > Yes, glm(log(Y) ~ X, family=gaussian(link=identity)) -- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Email: pd....@cbs.dk Priv: pda...@gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
