Hi, vec1<- factor(1:5,levels=1:10) vec1 #[1] 1 2 3 4 5 #Levels: 1 2 3 4 5 6 7 8 9 10
vec2<-droplevels(vec1) levels(vec2) #[1] "1" "2" "3" "4" "5" vec2 #[1] 1 2 3 4 5 #Levels: 1 2 3 4 5 A.K. Hi all, I am having a bit of trouble using the levels() function. I have a factor with many elements, and when I use the function levels() to extract the list of unique elements, some of the elements returned are not actually in the factor. For example I would have this: > vector <- dataset$Benchmark > class(vector) [1] "factor" > length(vector) [1] 35615 > vector2 <- levels(vector) > length(which(!(vector2 %in% vector))) [1] 235 Does anyone know how this is possible? Many thanks! Borja ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
